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Popular >

4(isin(60))

Solution

4 (i sin (6 0^{\circ}))

Solution

23 i

Solution steps

4 (i sin (6 0^{\circ}))

= 4 i sin (6 0^{\circ})

Use the following trivial identity:

sin (6 0^{\circ}) = \frac{3}{2}

sin (6 0^{\circ})

sin (x)

periodicity table with

36 0^{\circ} n

cycle:

x 0 3 0^{\circ} 4 5^{\circ} 6 0^{\circ} 9 0^{\circ} 12 0^{\circ} 13 5^{\circ} 15 0^{\circ} sin (x) 0 \frac{1}{2} \frac{2}{2} \frac{3}{2} 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} x 18 0^{\circ} 21 0^{\circ} 22 5^{\circ} 24 0^{\circ} 27 0^{\circ} 30 0^{\circ} 31 5^{\circ} 33 0^{\circ} sin (x) 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2}

= \frac{3}{2}

= 4 i \frac{3}{2}

Simplify

4 i \frac{3}{2} : 23 i

4 i \frac{3}{2}

Multiply fractions:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{3 \cdot 4 i}{2}

Divide the numbers:

\frac{4}{2} = 2

= 23 i

= 23 i

Popular Examples

- cos (13 5^{\circ})

cos (13 9^{\circ})

cosh(0.942)sin(0.429)

cosh (0.942) sin (0.429)

sqrt(2*9.81*3.5*(cos(90)-cos(50)))

2 \cdot 9.81 \cdot 3.5 \cdot (cos (9 0^{\circ}) - cos (5 0^{\circ}))

sin(45)-cos(60)

sin (4 5^{\circ}) - cos (6 0^{\circ})

Frequently Asked Questions (FAQ)

What is the value of 4(isin(60)) ?
The value of 4(isin(60)) is 2sqrt(3)i