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6sin(2x-30)+2=0

解答

6 sin (2 x - 3 0^{\circ}) + 2 = 0

解答

x = 18 0^{\circ} n + 1 5^{\circ} - \frac{0.33983 \dots}{2}, x = 18 0^{\circ} n + 9 0^{\circ} + 1 5^{\circ} + \frac{0.33983 \dots}{2}

+1

弧度

x = \frac{π}{12} - \frac{0.33983 \dots}{2} + πn, x = \frac{π}{2} + \frac{π}{12} + \frac{0.33983 \dots}{2} + πn

求解步骤

6 sin (2 x - 3 0^{\circ}) + 2 = 0

将

2

到右边

6 sin (2 x - 3 0^{\circ}) + 2 = 0

两边减去

2

6 sin (2 x - 3 0^{\circ}) + 2 - 2 = 0 - 2

化简

6 sin (2 x - 3 0^{\circ}) = - 2

6 sin (2 x - 3 0^{\circ}) = - 2

两边除以

6

6 sin (2 x - 3 0^{\circ}) = - 2

两边除以

6

\frac{6 sin ( 2 x - 3 0 ^{\circ} )}{6} = \frac{- 2}{6}

化简

\frac{6 sin ( 2 x - 3 0 ^{\circ} )}{6} = \frac{- 2}{6}

化简

\frac{6 sin ( 2 x - 3 0 ^{\circ} )}{6} : sin (2 x - 3 0^{\circ})

\frac{6 sin ( 2 x - 3 0 ^{\circ} )}{6}

数字相除:

\frac{6}{6} = 1

= sin (2 x - 3 0^{\circ})

化简

\frac{- 2}{6} : - \frac{1}{3}

\frac{- 2}{6}

使用分式法则:

\frac{- a}{b} = - \frac{a}{b}

= - \frac{2}{6}

约分:

2

= - \frac{1}{3}

sin (2 x - 3 0^{\circ}) = - \frac{1}{3}

sin (2 x - 3 0^{\circ}) = - \frac{1}{3}

sin (2 x - 3 0^{\circ}) = - \frac{1}{3}

使用反三角函数性质

sin (2 x - 3 0^{\circ}) = - \frac{1}{3}

sin (2 x - 3 0^{\circ}) = - \frac{1}{3}

的通解

sin (x) = - a \Rightarrow x = arcsin (- a) + 36 0^{\circ} n, x = 18 0^{\circ} + arcsin (a) + 36 0^{\circ} n

2 x - 3 0^{\circ} = arcsin (- \frac{1}{3}) + 36 0^{\circ} n, 2 x - 3 0^{\circ} = 18 0^{\circ} + arcsin (\frac{1}{3}) + 36 0^{\circ} n

2 x - 3 0^{\circ} = arcsin (- \frac{1}{3}) + 36 0^{\circ} n, 2 x - 3 0^{\circ} = 18 0^{\circ} + arcsin (\frac{1}{3}) + 36 0^{\circ} n

解

2 x - 3 0^{\circ} = arcsin (- \frac{1}{3}) + 36 0^{\circ} n : x = 18 0^{\circ} n + 1 5^{\circ} - \frac{arcsin ( \frac{1}{3} )}{2}

2 x - 3 0^{\circ} = arcsin (- \frac{1}{3}) + 36 0^{\circ} n

化简

arcsin (- \frac{1}{3}) + 36 0^{\circ} n : - arcsin (\frac{1}{3}) + 36 0^{\circ} n

arcsin (- \frac{1}{3}) + 36 0^{\circ} n

利用以下特性:

arcsin (- x) = - arcsin (x)

arcsin (- \frac{1}{3}) = - arcsin (\frac{1}{3})

= - arcsin (\frac{1}{3}) + 36 0^{\circ} n

2 x - 3 0^{\circ} = - arcsin (\frac{1}{3}) + 36 0^{\circ} n

将

3 0^{\circ}

到右边

2 x - 3 0^{\circ} = - arcsin (\frac{1}{3}) + 36 0^{\circ} n

两边加上

3 0^{\circ}

2 x - 3 0^{\circ} + 3 0^{\circ} = - arcsin (\frac{1}{3}) + 36 0^{\circ} n + 3 0^{\circ}

化简

2 x = - arcsin (\frac{1}{3}) + 36 0^{\circ} n + 3 0^{\circ}

2 x = - arcsin (\frac{1}{3}) + 36 0^{\circ} n + 3 0^{\circ}

两边除以

2

2 x = - arcsin (\frac{1}{3}) + 36 0^{\circ} n + 3 0^{\circ}

两边除以

2

\frac{2 x}{2} = - \frac{arcsin ( \frac{1}{3} )}{2} + \frac{36 0 ^{\circ} n}{2} + \frac{3 0 ^{\circ}}{2}

化简

\frac{2 x}{2} = - \frac{arcsin ( \frac{1}{3} )}{2} + \frac{36 0 ^{\circ} n}{2} + \frac{3 0 ^{\circ}}{2}

化简

\frac{2 x}{2} : x

\frac{2 x}{2}

数字相除:

\frac{2}{2} = 1

= x

化简

- \frac{arcsin ( \frac{1}{3} )}{2} + \frac{36 0 ^{\circ} n}{2} + \frac{3 0 ^{\circ}}{2} : 18 0^{\circ} n + 1 5^{\circ} - \frac{arcsin ( \frac{1}{3} )}{2}

- \frac{arcsin ( \frac{1}{3} )}{2} + \frac{36 0 ^{\circ} n}{2} + \frac{3 0 ^{\circ}}{2}

对同类项分组

= \frac{36 0 ^{\circ} n}{2} + \frac{3 0 ^{\circ}}{2} - \frac{arcsin ( \frac{1}{3} )}{2}

\frac{36 0 ^{\circ} n}{2} = 18 0^{\circ} n

\frac{36 0 ^{\circ} n}{2}

数字相除:

\frac{2}{2} = 1

= 18 0^{\circ} n

\frac{3 0 ^{\circ}}{2} = 1 5^{\circ}

\frac{3 0 ^{\circ}}{2}

使用分式法则:

\frac{\frac{b}{c}}{a} = \frac{b}{c \cdot a}

= \frac{18 0 ^{\circ}}{6 \cdot 2}

数字相乘:

6 \cdot 2 = 12

= 1 5^{\circ}

= 18 0^{\circ} n + 1 5^{\circ} - \frac{arcsin ( \frac{1}{3} )}{2}

x = 18 0^{\circ} n + 1 5^{\circ} - \frac{arcsin ( \frac{1}{3} )}{2}

x = 18 0^{\circ} n + 1 5^{\circ} - \frac{arcsin ( \frac{1}{3} )}{2}

x = 18 0^{\circ} n + 1 5^{\circ} - \frac{arcsin ( \frac{1}{3} )}{2}

解

2 x - 3 0^{\circ} = 18 0^{\circ} + arcsin (\frac{1}{3}) + 36 0^{\circ} n : x = 18 0^{\circ} n + 9 0^{\circ} + 1 5^{\circ} + \frac{arcsin ( \frac{1}{3} )}{2}

2 x - 3 0^{\circ} = 18 0^{\circ} + arcsin (\frac{1}{3}) + 36 0^{\circ} n

将

3 0^{\circ}

到右边

2 x - 3 0^{\circ} = 18 0^{\circ} + arcsin (\frac{1}{3}) + 36 0^{\circ} n

两边加上

3 0^{\circ}

2 x - 3 0^{\circ} + 3 0^{\circ} = 18 0^{\circ} + arcsin (\frac{1}{3}) + 36 0^{\circ} n + 3 0^{\circ}

化简

2 x = 18 0^{\circ} + arcsin (\frac{1}{3}) + 36 0^{\circ} n + 3 0^{\circ}

2 x = 18 0^{\circ} + arcsin (\frac{1}{3}) + 36 0^{\circ} n + 3 0^{\circ}

两边除以

2

2 x = 18 0^{\circ} + arcsin (\frac{1}{3}) + 36 0^{\circ} n + 3 0^{\circ}

两边除以

2

\frac{2 x}{2} = 9 0^{\circ} + \frac{arcsin ( \frac{1}{3} )}{2} + \frac{36 0 ^{\circ} n}{2} + \frac{3 0 ^{\circ}}{2}

化简

\frac{2 x}{2} = 9 0^{\circ} + \frac{arcsin ( \frac{1}{3} )}{2} + \frac{36 0 ^{\circ} n}{2} + \frac{3 0 ^{\circ}}{2}

化简

\frac{2 x}{2} : x

\frac{2 x}{2}

数字相除:

\frac{2}{2} = 1

= x

化简

9 0^{\circ} + \frac{arcsin ( \frac{1}{3} )}{2} + \frac{36 0 ^{\circ} n}{2} + \frac{3 0 ^{\circ}}{2} : 18 0^{\circ} n + 9 0^{\circ} + 1 5^{\circ} + \frac{arcsin ( \frac{1}{3} )}{2}

9 0^{\circ} + \frac{arcsin ( \frac{1}{3} )}{2} + \frac{36 0 ^{\circ} n}{2} + \frac{3 0 ^{\circ}}{2}

对同类项分组

= 9 0^{\circ} + \frac{36 0 ^{\circ} n}{2} + \frac{3 0 ^{\circ}}{2} + \frac{arcsin ( \frac{1}{3} )}{2}

\frac{36 0 ^{\circ} n}{2} = 18 0^{\circ} n

\frac{36 0 ^{\circ} n}{2}

数字相除:

\frac{2}{2} = 1

= 18 0^{\circ} n

\frac{3 0 ^{\circ}}{2} = 1 5^{\circ}

\frac{3 0 ^{\circ}}{2}

使用分式法则:

\frac{\frac{b}{c}}{a} = \frac{b}{c \cdot a}

= \frac{18 0 ^{\circ}}{6 \cdot 2}

数字相乘:

6 \cdot 2 = 12

= 1 5^{\circ}

= 9 0^{\circ} + 18 0^{\circ} n + 1 5^{\circ} + \frac{arcsin ( \frac{1}{3} )}{2}

对同类项分组

= 18 0^{\circ} n + 9 0^{\circ} + 1 5^{\circ} + \frac{arcsin ( \frac{1}{3} )}{2}

x = 18 0^{\circ} n + 9 0^{\circ} + 1 5^{\circ} + \frac{arcsin ( \frac{1}{3} )}{2}

x = 18 0^{\circ} n + 9 0^{\circ} + 1 5^{\circ} + \frac{arcsin ( \frac{1}{3} )}{2}

x = 18 0^{\circ} n + 9 0^{\circ} + 1 5^{\circ} + \frac{arcsin ( \frac{1}{3} )}{2}

x = 18 0^{\circ} n + 1 5^{\circ} - \frac{arcsin ( \frac{1}{3} )}{2}, x = 18 0^{\circ} n + 9 0^{\circ} + 1 5^{\circ} + \frac{arcsin ( \frac{1}{3} )}{2}

以小数形式表示解

x = 18 0^{\circ} n + 1 5^{\circ} - \frac{0.33983 \dots}{2}, x = 18 0^{\circ} n + 9 0^{\circ} + 1 5^{\circ} + \frac{0.33983 \dots}{2}

流行的例子

sin(x)=sin(pi/(10))

sin (x) = sin (\frac{π}{10})

1/(sqrt(2))=sin(x)

\frac{1}{2} = sin (x)

sin(3x)-sin(x)=-2sin(2x)sin(x)

sin (3 x) - sin (x) = - 2 sin (2 x) sin (x)

solvefor x,0.05cos(x)=-sin(x)求解

x, 0.05 cos (x) = - sin (x)

cos(x)=(20.26)/(26.4473)

cos (x^{\circ}) = \frac{20.26}{26.4473}