What is the general solution for arctan(θ)= pi/4 ?

The general solution for arctan(θ)= pi/4 is θ=1

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arctan(θ)= pi/4

arctan (θ) = \frac{π}{4}

θ = 1

Solution steps

arctan (θ) = \frac{π}{4}

Apply trig inverse properties

arctan (θ) = \frac{π}{4}

arctan (x) = a \Rightarrow x = tan (a)

θ = tan (\frac{π}{4})

tan (\frac{π}{4}) = 1

tan (\frac{π}{4})

Use the following trivial identity:

tan (\frac{π}{4}) = 1

tan (\frac{π}{4})

tan (x)

periodicity table with

πn

cycle:

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} tan (x) 0 \frac{3}{3} 13 \pm \infty - 3 - 1 - \frac{3}{3}

= 1

= 1

θ = 1

θ = 1

4 cos^{3} (x) - 7 cos (x) - 3 = 0

\frac{sin ( θ )}{1.3} = \frac{sin ( 12 5 ^{\circ} )}{2.8519}

cot^{2} (θ) = \frac{1}{3}

x, y^{3} - sin^{2} (x) = 1

- cos (2 x) - 4 sin^{2} (x) + 2 = 0

What is the general solution for arctan(θ)= pi/4 ?
The general solution for arctan(θ)= pi/4 is θ=1