What is the general solution for sin(θ)= 9/11 ?

The general solution for sin(θ)= 9/11 is θ=0.95824…+2pin,θ=pi-0.95824…+2pin

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sin(θ)= 9/11

sin (θ) = \frac{9}{11}

θ = 0.95824 \dots + 2 πn, θ = π - 0.95824 \dots + 2 πn

Degrees

θ = 54.90319 \dots^{\circ} + 36 0^{\circ} n, θ = 125.09680 \dots^{\circ} + 36 0^{\circ} n

Solution steps

sin (θ) = \frac{9}{11}

Apply trig inverse properties

sin (θ) = \frac{9}{11}

General solutions for

sin (θ) = \frac{9}{11}

sin (x) = a \Rightarrow x = arcsin (a) + 2 πn, x = π - arcsin (a) + 2 πn

θ = arcsin (\frac{9}{11}) + 2 πn, θ = π - arcsin (\frac{9}{11}) + 2 πn

θ = arcsin (\frac{9}{11}) + 2 πn, θ = π - arcsin (\frac{9}{11}) + 2 πn

Show solutions in decimal form

θ = 0.95824 \dots + 2 πn, θ = π - 0.95824 \dots + 2 πn

- sin^{2} (x) + sin (x) = 0

3 sin^{2} (t) - 2 sin (t) - 1 = 0

3 sin^{2} (x) + cos^{2} (x) = 2

tan (2 x) = 4

2 sin (2 x) = 1, in t er v a l (0, 36 0^{\circ})

What is the general solution for sin(θ)= 9/11 ?
The general solution for sin(θ)= 9/11 is θ=0.95824…+2pin,θ=pi-0.95824…+2pin