What is the general solution for tan(x)=4-3cot(x) ?

The general solution for tan(x)=4-3cot(x) is x= pi/4+pin,x=1.24904…+pin

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tan(x)=4-3cot(x)

Solution

tan (x) = 4 - 3 cot (x)

Solution

x = \frac{π}{4} + πn, x = 1.24904 \dots + πn

Degrees

x = 4 5^{\circ} + 18 0^{\circ} n, x = 71.56505 \dots^{\circ} + 18 0^{\circ} n

Solution steps

tan (x) = 4 - 3 cot (x)

Subtract

4 - 3 cot (x)

from both sides

tan (x) - 4 + 3 cot (x) = 0

Rewrite using trig identities

- 4 + tan (x) + 3 cot (x)

Use the basic trigonometric identity:

tan (x) = \frac{1}{cot ( x )}

= - 4 + \frac{1}{cot ( x )} + 3 cot (x)

- 4 + \frac{1}{cot ( x )} + 3 cot (x) = 0

Solve by substitution

- 4 + \frac{1}{cot ( x )} + 3 cot (x) = 0

Let:

cot (x) = u

- 4 + \frac{1}{u} + 3 u = 0

- 4 + \frac{1}{u} + 3 u = 0 : u = 1, u = \frac{1}{3}

- 4 + \frac{1}{u} + 3 u = 0

Multiply both sides by

u

- 4 + \frac{1}{u} + 3 u = 0

Multiply both sides by

u

- 4 u + \frac{1}{u} u + 3 uu = 0 \cdot u

Simplify

- 4 u + \frac{1}{u} u + 3 uu = 0 \cdot u

Simplify

\frac{1}{u} u : 1

\frac{1}{u} u

Multiply fractions:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{1 \cdot u}{u}

Cancel the common factor:

u

= 1

Simplify

3 uu : 3 u^{2}

3 uu

Apply exponent rule:

a^{b} \cdot a^{c} = a^{b + c}

uu = u^{1 + 1}

= 3 u^{1 + 1}

Add the numbers:

1 + 1 = 2

= 3 u^{2}

Simplify

0 \cdot u : 0

0 \cdot u

Apply rule

0 \cdot a = 0

= 0

- 4 u + 1 + 3 u^{2} = 0

- 4 u + 1 + 3 u^{2} = 0

- 4 u + 1 + 3 u^{2} = 0

Solve

- 4 u + 1 + 3 u^{2} = 0 : u = 1, u = \frac{1}{3}

- 4 u + 1 + 3 u^{2} = 0

Write in the standard form

a x^{2} + b x + c = 0

3 u^{2} - 4 u + 1 = 0

Solve with the quadratic formula

3 u^{2} - 4 u + 1 = 0

Quadratic Equation Formula:

For

a = 3, b = - 4, c = 1

u_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 \cdot 3 \cdot 1}{2 \cdot 3}

u_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 \cdot 3 \cdot 1}{2 \cdot 3}

(- 4)^{2} - 4 \cdot 3 \cdot 1 = 2

(- 4)^{2} - 4 \cdot 3 \cdot 1

Apply exponent rule:

(- a)^{n} = a^{n},

n

is even

(- 4)^{2} = 4^{2}

= 4^{2} - 4 \cdot 3 \cdot 1

Multiply the numbers:

4 \cdot 3 \cdot 1 = 12

= 4^{2} - 12

4^{2} = 16

= 16 - 12

Subtract the numbers:

16 - 12 = 4

= 4

Factor the number:

4 = 2^{2}

= 2^{2}

Apply radical rule:

2^{2} = 2

= 2

u_{1, 2} = \frac{- ( - 4 ) \pm 2}{2 \cdot 3}

Separate the solutions

u_{1} = \frac{- ( - 4 ) + 2}{2 \cdot 3}, u_{2} = \frac{- ( - 4 ) - 2}{2 \cdot 3}

u = \frac{- ( - 4 ) + 2}{2 \cdot 3} : 1

\frac{- ( - 4 ) + 2}{2 \cdot 3}

Apply rule

- (- a) = a

= \frac{4 + 2}{2 \cdot 3}

Add the numbers:

4 + 2 = 6

= \frac{6}{2 \cdot 3}

Multiply the numbers:

2 \cdot 3 = 6

= \frac{6}{6}

Apply rule

\frac{a}{a} = 1

= 1

u = \frac{- ( - 4 ) - 2}{2 \cdot 3} : \frac{1}{3}

\frac{- ( - 4 ) - 2}{2 \cdot 3}

Apply rule

- (- a) = a

= \frac{4 - 2}{2 \cdot 3}

Subtract the numbers:

4 - 2 = 2

= \frac{2}{2 \cdot 3}

Multiply the numbers:

2 \cdot 3 = 6

= \frac{2}{6}

Cancel the common factor:

2

= \frac{1}{3}

The solutions to the quadratic equation are:

u = 1, u = \frac{1}{3}

u = 1, u = \frac{1}{3}

Verify Solutions

Find undefined (singularity) points:

u = 0

Take the denominator(s) of

- 4 + \frac{1}{u} + 3 u

and compare to zero

u = 0

The following points are undefined

u = 0

Combine undefined points with solutions:

u = 1, u = \frac{1}{3}

Substitute back

u = cot (x)

cot (x) = 1, cot (x) = \frac{1}{3}

cot (x) = 1, cot (x) = \frac{1}{3}

cot (x) = 1 : x = \frac{π}{4} + πn

cot (x) = 1

General solutions for

cot (x) = 1

cot (x)

periodicity table with

πn

cycle:

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} cot (x) \mp \infty 31 \frac{3}{3} 0 - \frac{3}{3} - 1 - 3

x = \frac{π}{4} + πn

x = \frac{π}{4} + πn

cot (x) = \frac{1}{3} : x = arccot (\frac{1}{3}) + πn

cot (x) = \frac{1}{3}

Apply trig inverse properties

cot (x) = \frac{1}{3}

General solutions for

cot (x) = \frac{1}{3}

cot (x) = a \Rightarrow x = arccot (a) + πn

x = arccot (\frac{1}{3}) + πn

x = arccot (\frac{1}{3}) + πn

Combine all the solutions

x = \frac{π}{4} + πn, x = arccot (\frac{1}{3}) + πn

Show solutions in decimal form

x = \frac{π}{4} + πn, x = 1.24904 \dots + πn

Popular Examples

tan(x)=193.661

tan (x) = 193.661

sin(θ)=0.242

sin (θ) = 0.242

tan^2(45+(x/2))=4.137131

tan^{2} (4 5^{\circ} + (\frac{x}{2})^{\circ}) = 4.137131

2cos(x)=-1,0<= x<2pi

2 cos (x) = - 1, 0 \leq x < 2 π

cos(θ)= 3/(sqrt(11))

cos (θ) = \frac{3}{11}

Frequently Asked Questions (FAQ)

What is the general solution for tan(x)=4-3cot(x) ?
The general solution for tan(x)=4-3cot(x) is x= pi/4+pin,x=1.24904…+pin