What is the general solution for cos^2(x)-2cos(x)+1=0,0360 ?

The general solution for cos^2(x)-2cos(x)+1=0,0360 is No Solution for x\in\mathbb{R}

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cos^2(x)-2cos(x)+1=0,0360

cos^{2} (x) - 2 cos (x) + 1 = 0, 0^{\circ} 36 0^{\circ}

No Solution for x \in R

Solution steps

cos^{2} (x) - 2 cos (x) + 1 = 0, 0^{\circ} \cdot 36 0^{\circ}

Solve by substitution

cos^{2} (x) - 2 cos (x) + 1 = 0

Let:

cos (x) = u

u^{2} - 2 u + 1 = 0

u^{2} - 2 u + 1 = 0 : u = 1

u^{2} - 2 u + 1 = 0

Solve with the quadratic formula

u^{2} - 2 u + 1 = 0

Quadratic Equation Formula:

For

a = 1, b = - 2, c = 1

u_{1, 2} = \frac{- ( - 2 ) \pm ( - 2 ) ^{2} - 4 \cdot 1 \cdot 1}{2 \cdot 1}

u_{1, 2} = \frac{- ( - 2 ) \pm ( - 2 ) ^{2} - 4 \cdot 1 \cdot 1}{2 \cdot 1}

(- 2)^{2} - 4 \cdot 1 \cdot 1 = 0

(- 2)^{2} - 4 \cdot 1 \cdot 1

Apply exponent rule:

(- a)^{n} = a^{n},

n

is even

(- 2)^{2} = 2^{2}

= 2^{2} - 4 \cdot 1 \cdot 1

Multiply the numbers:

4 \cdot 1 \cdot 1 = 4

= 2^{2} - 4

2^{2} = 4

= 4 - 4

Subtract the numbers:

4 - 4 = 0

= 0

u_{1, 2} = \frac{- ( - 2 ) \pm 0}{2 \cdot 1}

u = \frac{- ( - 2 )}{2 \cdot 1}

\frac{- ( - 2 )}{2 \cdot 1} = 1

\frac{- ( - 2 )}{2 \cdot 1}

Apply rule

- (- a) = a

= \frac{2}{2 \cdot 1}

Multiply the numbers:

2 \cdot 1 = 2

= \frac{2}{2}

Apply rule

\frac{a}{a} = 1

= 1

u = 1

The solution to the quadratic equation is:

u = 1

Substitute back

u = cos (x)

cos (x) = 1

cos (x) = 1

cos (x) = 1, 0 \cdot 36 0^{\circ} :

No Solution

cos (x) = 1, 0 \cdot 36 0^{\circ}

General solutions for

cos (x) = 1

cos (x)

periodicity table with

36 0^{\circ} n

cycle:

x 0 3 0^{\circ} 4 5^{\circ} 6 0^{\circ} 9 0^{\circ} 12 0^{\circ} 13 5^{\circ} 15 0^{\circ} cos (x) 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} x 18 0^{\circ} 21 0^{\circ} 22 5^{\circ} 24 0^{\circ} 27 0^{\circ} 30 0^{\circ} 31 5^{\circ} 33 0^{\circ} cos (x) - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2} 0 \frac{1}{2} \frac{2}{2} \frac{3}{2}

x = 0 + 36 0^{\circ} n

x = 0 + 36 0^{\circ} n

Solve

x = 0 + 36 0^{\circ} n : x = 36 0^{\circ} n

x = 0 + 36 0^{\circ} n

0 + 36 0^{\circ} n = 36 0^{\circ} n

x = 36 0^{\circ} n

x = 36 0^{\circ} n

Solutions for the range

36 0^{\circ}

No Solution

Combine all the solutions

No Solution for x \in R

sin^{4} (x) = sin^{2} (x), 0 \leq x < 2 π

sin (θ) - 0.1 cos (θ) = \frac{6.88}{9.8}

sin (x) = 0.3352

tan^{2} (3 y) - 2 sec (3 y) - 2 = 0

cos^{2} (2 x) - sin^{2} (2 x) = 1

What is the general solution for cos^2(x)-2cos(x)+1=0,0360 ?
The general solution for cos^2(x)-2cos(x)+1=0,0360 is No Solution for x\in\mathbb{R}