What is the general solution for cos(x)= 3/5 ,cos(2pi+x) ?

The general solution for cos(x)= 3/5 ,cos(2pi+x) is No Solution for x\in\mathbb{R}

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cos(x)= 3/5 ,cos(2pi+x)

cos (x) = \frac{3}{5}, cos (2 π + x)

No Solution for x \in R

Solution steps

cos (x) = \frac{3}{5}, cos (2 π + x)

Apply trig inverse properties

cos (x) = \frac{3}{5}

General solutions for

cos (x) = \frac{3}{5}

cos (x) = a \Rightarrow x = arccos (a) + 2 πn, x = 2 π - arccos (a) + 2 πn

x = arccos (\frac{3}{5}) + 2 πn, x = 2 π - arccos (\frac{3}{5}) + 2 πn

x = arccos (\frac{3}{5}) + 2 πn, x = 2 π - arccos (\frac{3}{5}) + 2 πn

Solutions for the range

cos (2 π + x)

No Solution for x \in R

sin (4 5^{\circ}) = 1.57 \cdot sin (θ)

\frac{2}{3} = sec (x)

3 (cos (x) - 1) = - 1

9.6 8^{2} = 12. 5^{2} + 6.4 7^{2} - 2 \cdot 12.5 \cdot 6.47 \cdot cos (θ)

- 4 = \frac{sin ( θ )}{cos ( θ )}

What is the general solution for cos(x)= 3/5 ,cos(2pi+x) ?
The general solution for cos(x)= 3/5 ,cos(2pi+x) is No Solution for x\in\mathbb{R}