What is the general solution for tan(x)=-1,0<x<2pi ?

The general solution for tan(x)=-1,0<x<2pi is x=(3pi)/4 ,x=(7pi)/4

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tan(x)=-1,0<x<2pi

tan (x) = - 1, 0 < x < 2 π

x = \frac{3 π}{4}, x = \frac{7 π}{4}

Degrees

x = 13 5^{\circ}, x = 31 5^{\circ}

Solution steps

tan (x) = - 1, 0 < x < 2 π

General solutions for

tan (x) = - 1

tan (x)

periodicity table with

πn

cycle:

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} tan (x) 0 \frac{3}{3} 13 \pm \infty - 3 - 1 - \frac{3}{3}

x = \frac{3 π}{4} + πn

x = \frac{3 π}{4} + πn

Solutions for the range

0 < x < 2 π

x = \frac{3 π}{4}, x = \frac{7 π}{4}

sec^{2} (x) - 2 = tan^{2} (x), 0 \leq x \leq 2 π

sin (\frac{1}{2} x) = - \frac{1}{2}

4 cos (x) - 3 cos (x) - 1 = 0

3 sin (6 0^{\circ} - \frac{3 x}{4}) = 5 sin (\frac{3 x}{4} - 3 0^{\circ})

tan (u) = \frac{3}{3}

What is the general solution for tan(x)=-1,0<x<2pi ?
The general solution for tan(x)=-1,0<x<2pi is x=(3pi)/4 ,x=(7pi)/4