What is the general solution for cos(θ)= 8/25 ?

The general solution for cos(θ)= 8/25 is θ=1.24506…+2pin,θ=2pi-1.24506…+2pin

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cos(θ)= 8/25

cos (θ) = \frac{8}{25}

θ = 1.24506 \dots + 2 πn, θ = 2 π - 1.24506 \dots + 2 πn

Degrees

θ = 71.33707 \dots^{\circ} + 36 0^{\circ} n, θ = 288.66292 \dots^{\circ} + 36 0^{\circ} n

Solution steps

cos (θ) = \frac{8}{25}

Apply trig inverse properties

cos (θ) = \frac{8}{25}

General solutions for

cos (θ) = \frac{8}{25}

cos (x) = a \Rightarrow x = arccos (a) + 2 πn, x = 2 π - arccos (a) + 2 πn

θ = arccos (\frac{8}{25}) + 2 πn, θ = 2 π - arccos (\frac{8}{25}) + 2 πn

θ = arccos (\frac{8}{25}) + 2 πn, θ = 2 π - arccos (\frac{8}{25}) + 2 πn

Show solutions in decimal form

θ = 1.24506 \dots + 2 πn, θ = 2 π - 1.24506 \dots + 2 πn

sin (2 x) = π

sin (x + 5 π) = 0

cos (2 x) + 9 cos (x) + 5 = 0

25 = - 20 cos (\frac{2 π}{365} (x + 10)) + 25

sin (x) - cos (x) - \frac{1}{2} = 0

What is the general solution for cos(θ)= 8/25 ?
The general solution for cos(θ)= 8/25 is θ=1.24506…+2pin,θ=2pi-1.24506…+2pin