What is the general solution for cos(A)=(1^2+5.2^2-3.5)/(2(1)(5.2)) ?

The general solution for cos(A)=(1^2+5.2^2-3.5)/(2(1)(5.2)) is No Solution for A\in\mathbb{R}

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cos(A)=(1^2+5.2^2-3.5)/(2(1)(5.2))

cos (A) = \frac{1 ^{2} + 5. 2 ^{2} - 3.5}{2 ( 1 ) ( 5.2 )}

No Solution for A \in R

Solution steps

cos (A) = \frac{1 ^{2} + 5. 2 ^{2} - 3.5}{2 ( 1 ) ( 5.2 )}

Simplify

\frac{1 ^{2} + 5. 2 ^{2} - 3.5}{2 \cdot 1 \cdot 5.2} : \frac{24.54}{10.4}

\frac{1 ^{2} + 5. 2 ^{2} - 3.5}{2 \cdot 1 \cdot 5.2}

Apply rule

1^{a} = 1

1^{2} = 1

= \frac{1 + 5. 2 ^{2} - 3.5}{2 \cdot 1 \cdot 5.2}

1 + 5. 2^{2} - 3.5 = 24.54

1 + 5. 2^{2} - 3.5

5. 2^{2} = 27.04

= 1 + 27.04 - 3.5

Add/Subtract the numbers:

1 + 27.04 - 3.5 = 24.54

= 24.54

= \frac{24.54}{2 \cdot 1 \cdot 5.2}

Multiply the numbers:

2 \cdot 1 \cdot 5.2 = 10.4

= \frac{24.54}{10.4}

- 1 \leq cos (x) \leq 1

No Solution for A \in R

cos (5 x) - cos (3 x) = sin (4 x)

cos (9 0^{\circ} - x) + csc (x) = \frac{5}{2}

x, sin (x) - csc (t) + 1 = 0

cos^{2} (x) = \frac{3}{4 \cdot 5 cos ^{2} ( x )}

\frac{cos ^{2} ( x )}{1 - cos ( x )} = 1 + cos (x)

What is the general solution for cos(A)=(1^2+5.2^2-3.5)/(2(1)(5.2)) ?
The general solution for cos(A)=(1^2+5.2^2-3.5)/(2(1)(5.2)) is No Solution for A\in\mathbb{R}