What is the general solution for 1=tan(t) ?

The general solution for 1=tan(t) is t= pi/4+pin

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1=tan(t)

1 = tan (t)

t = \frac{π}{4} + πn

Degrees

t = 4 5^{\circ} + 18 0^{\circ} n

Solution steps

1 = tan (t)

Switch sides

tan (t) = 1

General solutions for

tan (t) = 1

tan (x)

periodicity table with

πn

cycle:

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} tan (x) 0 \frac{3}{3} 13 \pm \infty - 3 - 1 - \frac{3}{3}

t = \frac{π}{4} + πn

t = \frac{π}{4} + πn

sin (c) = \frac{5 sin ( 14 0 ^{\circ} )}{7}

7 = 5 sin (θ) + 2

2 cos^{2} (θ) - 7 cos (θ) + 3 = 0, θ

2 (sin^{2} (x)) + 5 sin (x) - 3 = 0

cos^{2} (3 x) - sin^{2} (3 x) = - 1

What is the general solution for 1=tan(t) ?
The general solution for 1=tan(t) is t= pi/4+pin