What is the general solution for tan(A)= 5/12 ,b=3 ?

The general solution for tan(A)= 5/12 ,b=3 is No Solution for A\in\mathbb{R}

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tan(A)= 5/12 ,b=3

tan (A) = \frac{5}{12}, b = 3

No Solution for A \in R

Solution steps

tan (A) = \frac{5}{12}, b = 3

Apply trig inverse properties

tan (A) = \frac{5}{12}

General solutions for

tan (A) = \frac{5}{12}

tan (x) = a \Rightarrow x = arctan (a) + πn

A = arctan (\frac{5}{12}) + πn

A = arctan (\frac{5}{12}) + πn

Solutions for the range

b = 3

No Solution for A \in R

tan (2 β) = - \frac{4}{3}

4 cos^{2} (x) - 5 cos (x) - 6 = 0

3 sec^{2} (\frac{x}{2}) - 4 sec (\frac{x}{2}) - 4 = 0

tan (x) = \frac{3}{10 cos ( x )}, 0^{\circ} < x < 9 0^{\circ}

2 cos^{2} (x) - 3 cos (x) = 0, 0, 2 π

What is the general solution for tan(A)= 5/12 ,b=3 ?
The general solution for tan(A)= 5/12 ,b=3 is No Solution for A\in\mathbb{R}