What is the general solution for tan(x)=0,0<x<2pi ?

The general solution for tan(x)=0,0<x<2pi is x=pi

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

tan(x)=0,0<x<2pi

tan (x) = 0, 0 < x < 2 π

x = π

Degrees

x = 18 0^{\circ}

Solution steps

tan (x) = 0, 0 < x < 2 π

General solutions for

tan (x) = 0

tan (x)

periodicity table with

πn

cycle:

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} tan (x) 0 \frac{3}{3} 13 \pm \infty - 3 - 1 - \frac{3}{3}

x = 0 + πn

x = 0 + πn

Solve

x = 0 + πn : x = πn

x = 0 + πn

0 + πn = πn

x = πn

x = πn

Solutions for the range

0 < x < 2 π

x = π

x, sin (x) + cos (y) = 2 y

4 sin (b) + 8 = 0

sin (x) = \frac{73}{83}

cos (2 B) = \frac{21}{35}

sin^{2} (x) = cos (x) - cos^{2} (x)

What is the general solution for tan(x)=0,0<x<2pi ?
The general solution for tan(x)=0,0<x<2pi is x=pi