What is the general solution for sin(x)=(48*sin(69))/(47.5) ?

The general solution for sin(x)=(48*sin(69))/(47.5) is x=1.23275…+360n,x=180-1.23275…+360n

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sin(x)=(48*sin(69))/(47.5)

sin (x) = \frac{48 \cdot sin ( 6 9 ^{\circ} )}{47.5}

x = 1.23275 \dots + 36 0^{\circ} n, x = 18 0^{\circ} - 1.23275 \dots + 36 0^{\circ} n

Radians

x = 1.23275 \dots + 2 πn, x = π - 1.23275 \dots + 2 πn

Solution steps

sin (x) = \frac{48 sin ( 6 9 ^{\circ} )}{47.5}

Apply trig inverse properties

sin (x) = \frac{48 sin ( 6 9 ^{\circ} )}{47.5}

General solutions for

sin (x) = \frac{48 sin ( 6 9 ^{\circ} )}{47.5}

sin (x) = a \Rightarrow x = arcsin (a) + 36 0^{\circ} n, x = 18 0^{\circ} - arcsin (a) + 36 0^{\circ} n

x = arcsin (\frac{48 sin ( 6 9 ^{\circ} )}{47.5}) + 36 0^{\circ} n, x = 18 0^{\circ} - arcsin (\frac{48 sin ( 6 9 ^{\circ} )}{47.5}) + 36 0^{\circ} n

x = arcsin (\frac{48 sin ( 6 9 ^{\circ} )}{47.5}) + 36 0^{\circ} n, x = 18 0^{\circ} - arcsin (\frac{48 sin ( 6 9 ^{\circ} )}{47.5}) + 36 0^{\circ} n

Show solutions in decimal form

x = 1.23275 \dots + 36 0^{\circ} n, x = 18 0^{\circ} - 1.23275 \dots + 36 0^{\circ} n

cos (x) = \frac{8 3}{16}

x, cos^{2} (x) = 0

cos (θ) = \frac{7}{4}

sin (2 θ - \frac{π}{2}) = - 1, 0 \leq θ \leq 2 π

sin (\frac{π}{11}) = sin (\frac{x π}{11})

What is the general solution for sin(x)=(48*sin(69))/(47.5) ?
The general solution for sin(x)=(48*sin(69))/(47.5) is x=1.23275…+360n,x=180-1.23275…+360n