What is the general solution for cos(t)+cos(2t)=0,sin(t)+sin(2t)=0 ?

The general solution for cos(t)+cos(2t)=0,sin(t)+sin(2t)=0 is No Solution for t\in\mathbb{R}

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cos(t)+cos(2t)=0,sin(t)+sin(2t)=0

Solution

cos (t) + cos (2 t) = 0, sin (t) + sin (2 t) = 0

Solution

No Solution for t \in R

Solution steps

cos (t) + cos (2 t) = 0, sin (t) + sin (2 t) = 0

Rewrite using trig identities

cos (2 t) + cos (t)

Use the Sum to Product identity:

cos (s) + cos (t) = 2 cos (\frac{s + t}{2}) cos (\frac{s - t}{2})

= 2 cos (\frac{2 t + t}{2}) cos (\frac{2 t - t}{2})

Simplify

2 cos (\frac{2 t + t}{2}) cos (\frac{2 t - t}{2}) : 2 cos (\frac{3 t}{2}) cos (\frac{t}{2})

2 cos (\frac{2 t + t}{2}) cos (\frac{2 t - t}{2})

Add similar elements:

2 t + t = 3 t

= 2 cos (\frac{3 t}{2}) cos (\frac{2 t - t}{2})

Add similar elements:

2 t - t = t

= 2 cos (\frac{3 t}{2}) cos (\frac{t}{2})

= 2 cos (\frac{3 t}{2}) cos (\frac{t}{2})

2 cos (\frac{3 t}{2}) cos (\frac{t}{2}) = 0

Solving each part separately

cos (\frac{3 t}{2}) = 0 or cos (\frac{t}{2}) = 0

cos (\frac{3 t}{2}) = 0, sin (t) + sin (2 t) = 0 :

No Solution

cos (\frac{3 t}{2}) = 0, sin (t) + sin (2 t) = 0

General solutions for

cos (\frac{3 t}{2}) = 0

cos (x)

periodicity table with

2 πn

cycle:

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} cos (x) 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} x π \frac{7 π}{6} \frac{5 π}{4} \frac{4 π}{3} \frac{3 π}{2} \frac{5 π}{3} \frac{7 π}{4} \frac{11 π}{6} cos (x) - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2} 0 \frac{1}{2} \frac{2}{2} \frac{3}{2}

\frac{3 t}{2} = \frac{π}{2} + 2 πn, \frac{3 t}{2} = \frac{3 π}{2} + 2 πn

\frac{3 t}{2} = \frac{π}{2} + 2 πn, \frac{3 t}{2} = \frac{3 π}{2} + 2 πn

Solve

\frac{3 t}{2} = \frac{π}{2} + 2 πn : t = \frac{π}{3} + \frac{4 πn}{3}

\frac{3 t}{2} = \frac{π}{2} + 2 πn

Multiply both sides by

2

\frac{3 t}{2} = \frac{π}{2} + 2 πn

Multiply both sides by

2

\frac{2 \cdot 3 t}{2} = 2 \cdot \frac{π}{2} + 2 \cdot 2 πn

Simplify

\frac{2 \cdot 3 t}{2} = 2 \cdot \frac{π}{2} + 2 \cdot 2 πn

Simplify

\frac{2 \cdot 3 t}{2} : 3 t

\frac{2 \cdot 3 t}{2}

Multiply the numbers:

2 \cdot 3 = 6

= \frac{6 t}{2}

Divide the numbers:

\frac{6}{2} = 3

= 3 t

Simplify

2 \cdot \frac{π}{2} + 2 \cdot 2 πn : π + 4 πn

2 \cdot \frac{π}{2} + 2 \cdot 2 πn

2 \cdot \frac{π}{2} = π

2 \cdot \frac{π}{2}

Multiply fractions:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{π 2}{2}

Cancel the common factor:

2

= π

2 \cdot 2 πn = 4 πn

2 \cdot 2 πn

Multiply the numbers:

2 \cdot 2 = 4

= 4 πn

= π + 4 πn

3 t = π + 4 πn

3 t = π + 4 πn

3 t = π + 4 πn

Divide both sides by

3

3 t = π + 4 πn

Divide both sides by

3

\frac{3 t}{3} = \frac{π}{3} + \frac{4 πn}{3}

Simplify

t = \frac{π}{3} + \frac{4 πn}{3}

t = \frac{π}{3} + \frac{4 πn}{3}

Solve

\frac{3 t}{2} = \frac{3 π}{2} + 2 πn : t = π + \frac{4 πn}{3}

\frac{3 t}{2} = \frac{3 π}{2} + 2 πn

Multiply both sides by

2

\frac{3 t}{2} = \frac{3 π}{2} + 2 πn

Multiply both sides by

2

\frac{2 \cdot 3 t}{2} = 2 \cdot \frac{3 π}{2} + 2 \cdot 2 πn

Simplify

\frac{2 \cdot 3 t}{2} = 2 \cdot \frac{3 π}{2} + 2 \cdot 2 πn

Simplify

\frac{2 \cdot 3 t}{2} : 3 t

\frac{2 \cdot 3 t}{2}

Multiply the numbers:

2 \cdot 3 = 6

= \frac{6 t}{2}

Divide the numbers:

\frac{6}{2} = 3

= 3 t

Simplify

2 \cdot \frac{3 π}{2} + 2 \cdot 2 πn : 3 π + 4 πn

2 \cdot \frac{3 π}{2} + 2 \cdot 2 πn

2 \cdot \frac{3 π}{2} = 3 π

2 \cdot \frac{3 π}{2}

Multiply fractions:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{3 π 2}{2}

Cancel the common factor:

2

= 3 π

2 \cdot 2 πn = 4 πn

2 \cdot 2 πn

Multiply the numbers:

2 \cdot 2 = 4

= 4 πn

= 3 π + 4 πn

3 t = 3 π + 4 πn

3 t = 3 π + 4 πn

3 t = 3 π + 4 πn

Divide both sides by

3

3 t = 3 π + 4 πn

Divide both sides by

3

\frac{3 t}{3} = \frac{3 π}{3} + \frac{4 πn}{3}

Simplify

t = π + \frac{4 πn}{3}

t = π + \frac{4 πn}{3}

t = \frac{π}{3} + \frac{4 πn}{3}, t = π + \frac{4 πn}{3}

Solutions for the range

sin (t) + sin (2 t) = 0

No Solution

cos (\frac{t}{2}) = 0, sin (t) + sin (2 t) = 0 :

No Solution

cos (\frac{t}{2}) = 0, sin (t) + sin (2 t) = 0

General solutions for

cos (\frac{t}{2}) = 0

cos (x)

periodicity table with

2 πn

cycle:

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} cos (x) 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} x π \frac{7 π}{6} \frac{5 π}{4} \frac{4 π}{3} \frac{3 π}{2} \frac{5 π}{3} \frac{7 π}{4} \frac{11 π}{6} cos (x) - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2} 0 \frac{1}{2} \frac{2}{2} \frac{3}{2}

\frac{t}{2} = \frac{π}{2} + 2 πn, \frac{t}{2} = \frac{3 π}{2} + 2 πn

\frac{t}{2} = \frac{π}{2} + 2 πn, \frac{t}{2} = \frac{3 π}{2} + 2 πn

Solve

\frac{t}{2} = \frac{π}{2} + 2 πn : t = π + 4 πn

\frac{t}{2} = \frac{π}{2} + 2 πn

Multiply both sides by

2

\frac{t}{2} = \frac{π}{2} + 2 πn

Multiply both sides by

2

\frac{2 t}{2} = 2 \cdot \frac{π}{2} + 2 \cdot 2 πn

Simplify

\frac{2 t}{2} = 2 \cdot \frac{π}{2} + 2 \cdot 2 πn

Simplify

\frac{2 t}{2} : t

\frac{2 t}{2}

Divide the numbers:

\frac{2}{2} = 1

= t

Simplify

2 \cdot \frac{π}{2} + 2 \cdot 2 πn : π + 4 πn

2 \cdot \frac{π}{2} + 2 \cdot 2 πn

2 \cdot \frac{π}{2} = π

2 \cdot \frac{π}{2}

Multiply fractions:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{π 2}{2}

Cancel the common factor:

2

= π

2 \cdot 2 πn = 4 πn

2 \cdot 2 πn

Multiply the numbers:

2 \cdot 2 = 4

= 4 πn

= π + 4 πn

t = π + 4 πn

t = π + 4 πn

t = π + 4 πn

Solve

\frac{t}{2} = \frac{3 π}{2} + 2 πn : t = 3 π + 4 πn

\frac{t}{2} = \frac{3 π}{2} + 2 πn

Multiply both sides by

2

\frac{t}{2} = \frac{3 π}{2} + 2 πn

Multiply both sides by

2

\frac{2 t}{2} = 2 \cdot \frac{3 π}{2} + 2 \cdot 2 πn

Simplify

\frac{2 t}{2} = 2 \cdot \frac{3 π}{2} + 2 \cdot 2 πn

Simplify

\frac{2 t}{2} : t

\frac{2 t}{2}

Divide the numbers:

\frac{2}{2} = 1

= t

Simplify

2 \cdot \frac{3 π}{2} + 2 \cdot 2 πn : 3 π + 4 πn

2 \cdot \frac{3 π}{2} + 2 \cdot 2 πn

2 \cdot \frac{3 π}{2} = 3 π

2 \cdot \frac{3 π}{2}

Multiply fractions:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{3 π 2}{2}

Cancel the common factor:

2

= 3 π

2 \cdot 2 πn = 4 πn

2 \cdot 2 πn

Multiply the numbers:

2 \cdot 2 = 4

= 4 πn

= 3 π + 4 πn

t = 3 π + 4 πn

t = 3 π + 4 πn

t = 3 π + 4 πn

t = π + 4 πn, t = 3 π + 4 πn

Solutions for the range

sin (t) + sin (2 t) = 0

No Solution

Combine all the solutions

No Solution for t \in R

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sin (x) = \frac{14}{16}

csc(A)=1.2384

csc (A) = 1.2384

cos(8t)cos(5t)=-sin(8t)sin(5t)

cos (8 t) cos (5 t) = - sin (8 t) sin (5 t)

2cos(θ)-3=-5,0<= θ<2pi

2 cos (θ) - 3 = - 5, 0 \leq θ < 2 π

Frequently Asked Questions (FAQ)

What is the general solution for cos(t)+cos(2t)=0,sin(t)+sin(2t)=0 ?
The general solution for cos(t)+cos(2t)=0,sin(t)+sin(2t)=0 is No Solution for t\in\mathbb{R}