What is the general solution for cos^2(x+30)= 1/4 ?

The general solution for cos^2(x+30)= 1/4 is x=360n+30,x=360n+270,x=360n+90,x=360n+210

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cos^2(x+30)= 1/4

Solution

cos^{2} (x + 3 0^{\circ}) = \frac{1}{4}

Solution

x = 36 0^{\circ} n + 3 0^{\circ}, x = 36 0^{\circ} n + 27 0^{\circ}, x = 36 0^{\circ} n + 9 0^{\circ}, x = 36 0^{\circ} n + 21 0^{\circ}

Radians

x = \frac{π}{6} + 2 πn, x = \frac{3 π}{2} + 2 πn, x = \frac{π}{2} + 2 πn, x = \frac{7 π}{6} + 2 πn

Solution steps

cos^{2} (x + 3 0^{\circ}) = \frac{1}{4}

Solve by substitution

cos^{2} (x + 3 0^{\circ}) = \frac{1}{4}

Let:

cos (x + 3 0^{\circ}) = u

u^{2} = \frac{1}{4}

u^{2} = \frac{1}{4} : u = \frac{1}{2}, u = - \frac{1}{2}

u^{2} = \frac{1}{4}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

u = \frac{1}{4}, u = - \frac{1}{4}

\frac{1}{4} = \frac{1}{2}

\frac{1}{4}

Apply radical rule:

assuming

a \geq 0, b \geq 0

= \frac{1}{4}

4 = 2

4

Factor the number:

4 = 2^{2}

= 2^{2}

Apply radical rule:

2^{2} = 2

= 2

= \frac{1}{2}

Apply rule

1 = 1

= \frac{1}{2}

- \frac{1}{4} = - \frac{1}{2}

- \frac{1}{4}

Simplify

\frac{1}{4} : \frac{1}{2}

\frac{1}{4}

Apply radical rule:

assuming

a \geq 0, b \geq 0

= \frac{1}{4}

4 = 2

4

Factor the number:

4 = 2^{2}

= 2^{2}

Apply radical rule:

2^{2} = 2

= 2

= \frac{1}{2}

= - \frac{1}{2}

Apply rule

1 = 1

= - \frac{1}{2}

u = \frac{1}{2}, u = - \frac{1}{2}

Substitute back

u = cos (x + 3 0^{\circ})

cos (x + 3 0^{\circ}) = \frac{1}{2}, cos (x + 3 0^{\circ}) = - \frac{1}{2}

cos (x + 3 0^{\circ}) = \frac{1}{2}, cos (x + 3 0^{\circ}) = - \frac{1}{2}

cos (x + 3 0^{\circ}) = \frac{1}{2} : x = 36 0^{\circ} n + 3 0^{\circ}, x = 36 0^{\circ} n + 27 0^{\circ}

cos (x + 3 0^{\circ}) = \frac{1}{2}

General solutions for

cos (x + 3 0^{\circ}) = \frac{1}{2}

cos (x)

periodicity table with

36 0^{\circ} n

cycle:

x 0 3 0^{\circ} 4 5^{\circ} 6 0^{\circ} 9 0^{\circ} 12 0^{\circ} 13 5^{\circ} 15 0^{\circ} cos (x) 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} x 18 0^{\circ} 21 0^{\circ} 22 5^{\circ} 24 0^{\circ} 27 0^{\circ} 30 0^{\circ} 31 5^{\circ} 33 0^{\circ} cos (x) - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2} 0 \frac{1}{2} \frac{2}{2} \frac{3}{2}

x + 3 0^{\circ} = 6 0^{\circ} + 36 0^{\circ} n, x + 3 0^{\circ} = 30 0^{\circ} + 36 0^{\circ} n

x + 3 0^{\circ} = 6 0^{\circ} + 36 0^{\circ} n, x + 3 0^{\circ} = 30 0^{\circ} + 36 0^{\circ} n

Solve

x + 3 0^{\circ} = 6 0^{\circ} + 36 0^{\circ} n : x = 36 0^{\circ} n + 3 0^{\circ}

x + 3 0^{\circ} = 6 0^{\circ} + 36 0^{\circ} n

Move

3 0^{\circ}

to the right side

x + 3 0^{\circ} = 6 0^{\circ} + 36 0^{\circ} n

Subtract

3 0^{\circ}

from both sides

x + 3 0^{\circ} - 3 0^{\circ} = 6 0^{\circ} + 36 0^{\circ} n - 3 0^{\circ}

Simplify

x + 3 0^{\circ} - 3 0^{\circ} = 6 0^{\circ} + 36 0^{\circ} n - 3 0^{\circ}

Simplify

x + 3 0^{\circ} - 3 0^{\circ} : x

x + 3 0^{\circ} - 3 0^{\circ}

Add similar elements:

3 0^{\circ} - 3 0^{\circ} = 0

= x

Simplify

6 0^{\circ} + 36 0^{\circ} n - 3 0^{\circ} : 36 0^{\circ} n + 3 0^{\circ}

6 0^{\circ} + 36 0^{\circ} n - 3 0^{\circ}

Group like terms

= 36 0^{\circ} n + 6 0^{\circ} - 3 0^{\circ}

Least Common Multiplier of

3, 6 : 6

3, 6

Least Common Multiplier (LCM)

Prime factorization of

3 : 3

3

3

is a prime number, therefore no factorization is possible

= 3

Prime factorization of

6 : 2 \cdot 3

6

6

divides by

26 = 3 \cdot 2

= 2 \cdot 3

2, 3

are all prime numbers, therefore no further factorization is possible

= 2 \cdot 3

Multiply each factor the greatest number of times it occurs in either

3

6

= 3 \cdot 2

Multiply the numbers:

3 \cdot 2 = 6

= 6

Adjust Fractions based on the LCM

Multiply each numerator by the same amount needed to multiply its

corresponding denominator to turn it into the LCM

6

For

6 0^{\circ} :

multiply the denominator and numerator by

2

6 0^{\circ} = \frac{18 0 ^{\circ} 2}{3 \cdot 2} = 6 0^{\circ}

= 6 0^{\circ} - 3 0^{\circ}

Since the denominators are equal, combine the fractions:

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{18 0 ^{\circ} 2 - 18 0 ^{\circ}}{6}

Add similar elements:

36 0^{\circ} - 18 0^{\circ} = 18 0^{\circ}

= 36 0^{\circ} n + 3 0^{\circ}

x = 36 0^{\circ} n + 3 0^{\circ}

x = 36 0^{\circ} n + 3 0^{\circ}

x = 36 0^{\circ} n + 3 0^{\circ}

Solve

x + 3 0^{\circ} = 30 0^{\circ} + 36 0^{\circ} n : x = 36 0^{\circ} n + 27 0^{\circ}

x + 3 0^{\circ} = 30 0^{\circ} + 36 0^{\circ} n

Move

3 0^{\circ}

to the right side

x + 3 0^{\circ} = 30 0^{\circ} + 36 0^{\circ} n

Subtract

3 0^{\circ}

from both sides

x + 3 0^{\circ} - 3 0^{\circ} = 30 0^{\circ} + 36 0^{\circ} n - 3 0^{\circ}

Simplify

x + 3 0^{\circ} - 3 0^{\circ} = 30 0^{\circ} + 36 0^{\circ} n - 3 0^{\circ}

Simplify

x + 3 0^{\circ} - 3 0^{\circ} : x

x + 3 0^{\circ} - 3 0^{\circ}

Add similar elements:

3 0^{\circ} - 3 0^{\circ} = 0

= x

Simplify

30 0^{\circ} + 36 0^{\circ} n - 3 0^{\circ} : 36 0^{\circ} n + 27 0^{\circ}

30 0^{\circ} + 36 0^{\circ} n - 3 0^{\circ}

Group like terms

= 36 0^{\circ} n - 3 0^{\circ} + 30 0^{\circ}

Least Common Multiplier of

6, 3 : 6

6, 3

Least Common Multiplier (LCM)

Prime factorization of

6 : 2 \cdot 3

6

6

divides by

26 = 3 \cdot 2

= 2 \cdot 3

2, 3

are all prime numbers, therefore no further factorization is possible

= 2 \cdot 3

Prime factorization of

3 : 3

3

3

is a prime number, therefore no factorization is possible

= 3

Multiply each factor the greatest number of times it occurs in either

6

3

= 2 \cdot 3

Multiply the numbers:

2 \cdot 3 = 6

= 6

Adjust Fractions based on the LCM

Multiply each numerator by the same amount needed to multiply its

corresponding denominator to turn it into the LCM

6

For

30 0^{\circ} :

multiply the denominator and numerator by

2

30 0^{\circ} = \frac{90 0 ^{\circ} 2}{3 \cdot 2} = 30 0^{\circ}

= - 3 0^{\circ} + 30 0^{\circ}

Since the denominators are equal, combine the fractions:

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{- 18 0 ^{\circ} + 180 0 ^{\circ}}{6}

Add similar elements:

- 18 0^{\circ} + 180 0^{\circ} = 162 0^{\circ}

= 27 0^{\circ}

Cancel the common factor:

3

= 36 0^{\circ} n + 27 0^{\circ}

x = 36 0^{\circ} n + 27 0^{\circ}

x = 36 0^{\circ} n + 27 0^{\circ}

x = 36 0^{\circ} n + 27 0^{\circ}

x = 36 0^{\circ} n + 3 0^{\circ}, x = 36 0^{\circ} n + 27 0^{\circ}

cos (x + 3 0^{\circ}) = - \frac{1}{2} : x = 36 0^{\circ} n + 9 0^{\circ}, x = 36 0^{\circ} n + 21 0^{\circ}

cos (x + 3 0^{\circ}) = - \frac{1}{2}

General solutions for

cos (x + 3 0^{\circ}) = - \frac{1}{2}

cos (x)

periodicity table with

36 0^{\circ} n

cycle:

x 0 3 0^{\circ} 4 5^{\circ} 6 0^{\circ} 9 0^{\circ} 12 0^{\circ} 13 5^{\circ} 15 0^{\circ} cos (x) 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} x 18 0^{\circ} 21 0^{\circ} 22 5^{\circ} 24 0^{\circ} 27 0^{\circ} 30 0^{\circ} 31 5^{\circ} 33 0^{\circ} cos (x) - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2} 0 \frac{1}{2} \frac{2}{2} \frac{3}{2}

x + 3 0^{\circ} = 12 0^{\circ} + 36 0^{\circ} n, x + 3 0^{\circ} = 24 0^{\circ} + 36 0^{\circ} n

x + 3 0^{\circ} = 12 0^{\circ} + 36 0^{\circ} n, x + 3 0^{\circ} = 24 0^{\circ} + 36 0^{\circ} n

Solve

x + 3 0^{\circ} = 12 0^{\circ} + 36 0^{\circ} n : x = 36 0^{\circ} n + 9 0^{\circ}

x + 3 0^{\circ} = 12 0^{\circ} + 36 0^{\circ} n

Move

3 0^{\circ}

to the right side

x + 3 0^{\circ} = 12 0^{\circ} + 36 0^{\circ} n

Subtract

3 0^{\circ}

from both sides

x + 3 0^{\circ} - 3 0^{\circ} = 12 0^{\circ} + 36 0^{\circ} n - 3 0^{\circ}

Simplify

x + 3 0^{\circ} - 3 0^{\circ} = 12 0^{\circ} + 36 0^{\circ} n - 3 0^{\circ}

Simplify

x + 3 0^{\circ} - 3 0^{\circ} : x

x + 3 0^{\circ} - 3 0^{\circ}

Add similar elements:

3 0^{\circ} - 3 0^{\circ} = 0

= x

Simplify

12 0^{\circ} + 36 0^{\circ} n - 3 0^{\circ} : 36 0^{\circ} n + 9 0^{\circ}

12 0^{\circ} + 36 0^{\circ} n - 3 0^{\circ}

Group like terms

= 36 0^{\circ} n - 3 0^{\circ} + 12 0^{\circ}

Least Common Multiplier of

6, 3 : 6

6, 3

Least Common Multiplier (LCM)

Prime factorization of

6 : 2 \cdot 3

6

6

divides by

26 = 3 \cdot 2

= 2 \cdot 3

2, 3

are all prime numbers, therefore no further factorization is possible

= 2 \cdot 3

Prime factorization of

3 : 3

3

3

is a prime number, therefore no factorization is possible

= 3

Multiply each factor the greatest number of times it occurs in either

6

3

= 2 \cdot 3

Multiply the numbers:

2 \cdot 3 = 6

= 6

Adjust Fractions based on the LCM

Multiply each numerator by the same amount needed to multiply its

corresponding denominator to turn it into the LCM

6

For

12 0^{\circ} :

multiply the denominator and numerator by

2

12 0^{\circ} = \frac{36 0 ^{\circ} 2}{3 \cdot 2} = 12 0^{\circ}

= - 3 0^{\circ} + 12 0^{\circ}

Since the denominators are equal, combine the fractions:

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{- 18 0 ^{\circ} + 72 0 ^{\circ}}{6}

Add similar elements:

- 18 0^{\circ} + 72 0^{\circ} = 54 0^{\circ}

= 9 0^{\circ}

Cancel the common factor:

3

= 36 0^{\circ} n + 9 0^{\circ}

x = 36 0^{\circ} n + 9 0^{\circ}

x = 36 0^{\circ} n + 9 0^{\circ}

x = 36 0^{\circ} n + 9 0^{\circ}

Solve

x + 3 0^{\circ} = 24 0^{\circ} + 36 0^{\circ} n : x = 36 0^{\circ} n + 21 0^{\circ}

x + 3 0^{\circ} = 24 0^{\circ} + 36 0^{\circ} n

Move

3 0^{\circ}

to the right side

x + 3 0^{\circ} = 24 0^{\circ} + 36 0^{\circ} n

Subtract

3 0^{\circ}

from both sides

x + 3 0^{\circ} - 3 0^{\circ} = 24 0^{\circ} + 36 0^{\circ} n - 3 0^{\circ}

Simplify

x + 3 0^{\circ} - 3 0^{\circ} = 24 0^{\circ} + 36 0^{\circ} n - 3 0^{\circ}

Simplify

x + 3 0^{\circ} - 3 0^{\circ} : x

x + 3 0^{\circ} - 3 0^{\circ}

Add similar elements:

3 0^{\circ} - 3 0^{\circ} = 0

= x

Simplify

24 0^{\circ} + 36 0^{\circ} n - 3 0^{\circ} : 36 0^{\circ} n + 21 0^{\circ}

24 0^{\circ} + 36 0^{\circ} n - 3 0^{\circ}

Group like terms

= 36 0^{\circ} n - 3 0^{\circ} + 24 0^{\circ}

Least Common Multiplier of

6, 3 : 6

6, 3

Least Common Multiplier (LCM)

Prime factorization of

6 : 2 \cdot 3

6

6

divides by

26 = 3 \cdot 2

= 2 \cdot 3

2, 3

are all prime numbers, therefore no further factorization is possible

= 2 \cdot 3

Prime factorization of

3 : 3

3

3

is a prime number, therefore no factorization is possible

= 3

Multiply each factor the greatest number of times it occurs in either

6

3

= 2 \cdot 3

Multiply the numbers:

2 \cdot 3 = 6

= 6

Adjust Fractions based on the LCM

Multiply each numerator by the same amount needed to multiply its

corresponding denominator to turn it into the LCM

6

For

24 0^{\circ} :

multiply the denominator and numerator by

2

24 0^{\circ} = \frac{72 0 ^{\circ} 2}{3 \cdot 2} = 24 0^{\circ}

= - 3 0^{\circ} + 24 0^{\circ}

Since the denominators are equal, combine the fractions:

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{- 18 0 ^{\circ} + 144 0 ^{\circ}}{6}

Add similar elements:

- 18 0^{\circ} + 144 0^{\circ} = 126 0^{\circ}

= 36 0^{\circ} n + 21 0^{\circ}

x = 36 0^{\circ} n + 21 0^{\circ}

x = 36 0^{\circ} n + 21 0^{\circ}

x = 36 0^{\circ} n + 21 0^{\circ}

x = 36 0^{\circ} n + 9 0^{\circ}, x = 36 0^{\circ} n + 21 0^{\circ}

Combine all the solutions

x = 36 0^{\circ} n + 3 0^{\circ}, x = 36 0^{\circ} n + 27 0^{\circ}, x = 36 0^{\circ} n + 9 0^{\circ}, x = 36 0^{\circ} n + 21 0^{\circ}

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Frequently Asked Questions (FAQ)

What is the general solution for cos^2(x+30)= 1/4 ?
The general solution for cos^2(x+30)= 1/4 is x=360n+30,x=360n+270,x=360n+90,x=360n+210