What is the general solution for sin(θ)=-(sqrt(35))/6 ?

The general solution for sin(θ)=-(sqrt(35))/6 is θ=-1.40334…+2pin,θ=pi+1.40334…+2pin

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sin(θ)=-(sqrt(35))/6

sin (θ) = - \frac{35}{6}

θ = - 1.40334 \dots + 2 πn, θ = π + 1.40334 \dots + 2 πn

Degrees

θ = - 80.40593 \dots^{\circ} + 36 0^{\circ} n, θ = 260.40593 \dots^{\circ} + 36 0^{\circ} n

Solution steps

sin (θ) = - \frac{35}{6}

Apply trig inverse properties

sin (θ) = - \frac{35}{6}

General solutions for

sin (θ) = - \frac{35}{6}

sin (x) = - a \Rightarrow x = arcsin (- a) + 2 πn, x = π + arcsin (a) + 2 πn

θ = arcsin (- \frac{35}{6}) + 2 πn, θ = π + arcsin (\frac{35}{6}) + 2 πn

θ = arcsin (- \frac{35}{6}) + 2 πn, θ = π + arcsin (\frac{35}{6}) + 2 πn

Show solutions in decimal form

θ = - 1.40334 \dots + 2 πn, θ = π + 1.40334 \dots + 2 πn

0.6 = cos (x)

3 tan^{3} (x) - 1 = 0

- 2 csc^{2} (2 x) = 0

1 - cos (θ) = 3 sin (θ)

tan^{2} (x) = 5 sin^{2} (x)

What is the general solution for sin(θ)=-(sqrt(35))/6 ?
The general solution for sin(θ)=-(sqrt(35))/6 is θ=-1.40334…+2pin,θ=pi+1.40334…+2pin