What is the general solution for (sin(A))/(cos(A))-2=1 ?

The general solution for (sin(A))/(cos(A))-2=1 is A=1.24904…+pin

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(sin(A))/(cos(A))-2=1

\frac{sin ( A )}{cos ( A )} - 2 = 1

A = 1.24904 \dots + πn

Degrees

A = 71.56505 \dots^{\circ} + 18 0^{\circ} n

Solution steps

\frac{sin ( A )}{cos ( A )} - 2 = 1

Rewrite using trig identities

\frac{sin ( A )}{cos ( A )} - 2

Use the basic trigonometric identity:

\frac{sin ( x )}{cos ( x )} = tan (x)

= tan (A) - 2

tan (A) - 2 = 1

Move

2

to the right side

tan (A) - 2 = 1

Add

2

to both sides

tan (A) - 2 + 2 = 1 + 2

Simplify

tan (A) = 3

tan (A) = 3

Apply trig inverse properties

tan (A) = 3

General solutions for

tan (A) = 3

tan (x) = a \Rightarrow x = arctan (a) + πn

A = arctan (3) + πn

A = arctan (3) + πn

Show solutions in decimal form

A = 1.24904 \dots + πn

cos (θ) = \frac{10}{15}

sin (θ) = \frac{40}{60}

10 = 3.44 sin (0.51 t + 4.11) + 9.48

2 cot^{2} (z) + 5 = 7 csc (z)

sin^{2} (x) = 6

What is the general solution for (sin(A))/(cos(A))-2=1 ?
The general solution for (sin(A))/(cos(A))-2=1 is A=1.24904…+pin