What is the general solution for sin(φ)=0 ?

The general solution for sin(φ)=0 is φ=2pin,φ=pi+2pin

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sin(φ)=0

sin (φ) = 0

φ = 2 πn, φ = π + 2 πn

Degrees

φ = 0^{\circ} + 36 0^{\circ} n, φ = 18 0^{\circ} + 36 0^{\circ} n

Solution steps

sin (φ) = 0

General solutions for

sin (φ) = 0

sin (x)

periodicity table with

2 πn

cycle:

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} sin (x) 0 \frac{1}{2} \frac{2}{2} \frac{3}{2} 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} x π \frac{7 π}{6} \frac{5 π}{4} \frac{4 π}{3} \frac{3 π}{2} \frac{5 π}{3} \frac{7 π}{4} \frac{11 π}{6} sin (x) 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2}

φ = 0 + 2 πn, φ = π + 2 πn

φ = 0 + 2 πn, φ = π + 2 πn

Solve

φ = 0 + 2 πn : φ = 2 πn

φ = 0 + 2 πn

0 + 2 πn = 2 πn

φ = 2 πn

φ = 2 πn, φ = π + 2 πn

sin^{2} (x) = 1 - tan^{2} (x), 0 \leq x \leq \frac{π}{2}

sin (0.3 x) = 1

22.89 = cos (a)

cos (x) = \frac{2}{2}

21.16 = 19.6 sin (x) - 29.4 cos (x)

What is the general solution for sin(φ)=0 ?
The general solution for sin(φ)=0 is φ=2pin,φ=pi+2pin