What is the general solution for (-1)/2 =cos(x) ?

The general solution for (-1)/2 =cos(x) is x=(2pi)/3+2pin,x=(4pi)/3+2pin

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(-1)/2 =cos(x)

\frac{- 1}{2} = cos (x)

x = \frac{2 π}{3} + 2 πn, x = \frac{4 π}{3} + 2 πn

Degrees

x = 12 0^{\circ} + 36 0^{\circ} n, x = 24 0^{\circ} + 36 0^{\circ} n

Solution steps

\frac{- 1}{2} = cos (x)

Switch sides

cos (x) = \frac{- 1}{2}

Apply the fraction rule:

\frac{- a}{b} = - \frac{a}{b}

cos (x) = - \frac{1}{2}

General solutions for

cos (x) = - \frac{1}{2}

cos (x)

periodicity table with

2 πn

cycle:

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} cos (x) 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} x π \frac{7 π}{6} \frac{5 π}{4} \frac{4 π}{3} \frac{3 π}{2} \frac{5 π}{3} \frac{7 π}{4} \frac{11 π}{6} cos (x) - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2} 0 \frac{1}{2} \frac{2}{2} \frac{3}{2}

x = \frac{2 π}{3} + 2 πn, x = \frac{4 π}{3} + 2 πn

x = \frac{2 π}{3} + 2 πn, x = \frac{4 π}{3} + 2 πn

cos (2 t) - sin (t) = 0.5, 0 \leq t \leq 2 π

sin (2 x) = 0.1

sin (\frac{π}{2} - x) tan (x) = cos (x)

sin (x) = \frac{3}{2}, 0 \leq x \leq 2 π

2 = - 8 \cdot sin (4 x)

What is the general solution for (-1)/2 =cos(x) ?
The general solution for (-1)/2 =cos(x) is x=(2pi)/3+2pin,x=(4pi)/3+2pin