What is the general solution for solvefor x,sec(x)+sqrt(2)=0 ?

The general solution for solvefor x,sec(x)+sqrt(2)=0 is x=(3pi)/4+2pin,x=(5pi)/4+2pin

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solvefor x,sec(x)+sqrt(2)=0

solve for

x, sec (x) + 2 = 0

x = \frac{3 π}{4} + 2 πn, x = \frac{5 π}{4} + 2 πn

Degrees

x = 13 5^{\circ} + 36 0^{\circ} n, x = 22 5^{\circ} + 36 0^{\circ} n

Solution steps

sec (x) + 2 = 0

Move

2

to the right side

sec (x) + 2 = 0

Subtract

2

from both sides

sec (x) + 2 - 2 = 0 - 2

Simplify

sec (x) = - 2

sec (x) = - 2

General solutions for

sec (x) = - 2

sec (x)

periodicity table with

2 πn

cycle:

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} sec (x) 1 \frac{2 3}{3} 22 Undefined - 2 - 2 - \frac{2 3}{3} x π \frac{7 π}{6} \frac{5 π}{4} \frac{4 π}{3} \frac{3 π}{2} \frac{5 π}{3} \frac{7 π}{4} \frac{11 π}{6} sec (x) - 1 - \frac{2 3}{3} - 2 - 2 Undefined 22 \frac{2 3}{3}

x = \frac{3 π}{4} + 2 πn, x = \frac{5 π}{4} + 2 πn

x = \frac{3 π}{4} + 2 πn, x = \frac{5 π}{4} + 2 πn

cos (2 x) = 0.92

cos (4 x) + 1 = 3 sin (2 x), - \frac{π}{2} \leq x \leq \frac{π}{2}

3 - 6 cos (x + \frac{π}{3}) = 0

sin (7.07 t) = 0.5

tan (x) = \frac{1}{3}, 0 \leq x < 2 π

What is the general solution for solvefor x,sec(x)+sqrt(2)=0 ?
The general solution for solvefor x,sec(x)+sqrt(2)=0 is x=(3pi)/4+2pin,x=(5pi)/4+2pin