What is the general solution for sin(x)= 1/3 ,sec(y)=(25)/(24,cos(x+y)) ?

The general solution for sin(x)= 1/3 ,sec(y)=(25)/(24,cos(x+y)) is No Solution for x\in\mathbb{R}

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sin(x)= 1/3 ,sec(y)=(25)/(24,cos(x+y))

sin (x) = \frac{1}{3}, sec (y) = \frac{25}{24 , cos ( x + y )}

No Solution for x \in R

Solution steps

sin (x) = \frac{1}{3}, sec (y) = \frac{25}{24 , cos ( x + y )}

Apply trig inverse properties

sin (x) = \frac{1}{3}

General solutions for

sin (x) = \frac{1}{3}

sin (x) = a \Rightarrow x = arcsin (a) + 2 πn, x = π - arcsin (a) + 2 πn

x = arcsin (\frac{1}{3}) + 2 πn, x = π - arcsin (\frac{1}{3}) + 2 πn

x = arcsin (\frac{1}{3}) + 2 πn, x = π - arcsin (\frac{1}{3}) + 2 πn

Solutions for the range

sec (y) = \frac{25}{24 , cos ( x + y )}

No Solution for x \in R

2 = 2 - π cos (t)

a, 45 = arctanh (\frac{a}{b})

x, sec (x) = 3

cot (θ - 3 0^{\circ}) = \frac{1}{3}

(cot (x) - 3) (csc (x) + 2) = 0

What is the general solution for sin(x)= 1/3 ,sec(y)=(25)/(24,cos(x+y)) ?
The general solution for sin(x)= 1/3 ,sec(y)=(25)/(24,cos(x+y)) is No Solution for x\in\mathbb{R}