What is the general solution for cos(a)=-8/17 ,sin(b)= 3/5 ?

The general solution for cos(a)=-8/17 ,sin(b)= 3/5 is No Solution for a\in\mathbb{R}

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cos(a)=-8/17 ,sin(b)= 3/5

cos (a) = - \frac{8}{17}, sin (b) = \frac{3}{5}

No Solution for a \in R

Solution steps

cos (a) = - \frac{8}{17}, sin (b) = \frac{3}{5}

Apply trig inverse properties

cos (a) = - \frac{8}{17}

General solutions for

cos (a) = - \frac{8}{17}

cos (x) = - a \Rightarrow x = arccos (- a) + 2 πn, x = - arccos (- a) + 2 πn

a = arccos (- \frac{8}{17}) + 2 πn, a = - arccos (- \frac{8}{17}) + 2 πn

a = arccos (- \frac{8}{17}) + 2 πn, a = - arccos (- \frac{8}{17}) + 2 πn

Solutions for the range

sin (b) = \frac{3}{5}

No Solution for a \in R

7 tan (θ) + 9 = 0

14 = - 3.75 cos (\frac{π}{6} x) + 11.25

x, f = sin (π \cdot ⌊ x ⌋)

(sin (x)) (tan (x) + 1) (cos (x) + 1) = 0

tan (3.87 x) = - 0.78

What is the general solution for cos(a)=-8/17 ,sin(b)= 3/5 ?
The general solution for cos(a)=-8/17 ,sin(b)= 3/5 is No Solution for a\in\mathbb{R}