What is the general solution for sin(θ)= 3/5 ,sin(2θ) ?

The general solution for sin(θ)= 3/5 ,sin(2θ) is No Solution for θ\in\mathbb{R}

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sin(θ)= 3/5 ,sin(2θ)

sin (θ) = \frac{3}{5}, sin (2 θ)

No Solution for θ \in R

Solution steps

sin (θ) = \frac{3}{5}, sin (2 θ)

Apply trig inverse properties

sin (θ) = \frac{3}{5}

General solutions for

sin (θ) = \frac{3}{5}

sin (x) = a \Rightarrow x = arcsin (a) + 2 πn, x = π - arcsin (a) + 2 πn

θ = arcsin (\frac{3}{5}) + 2 πn, θ = π - arcsin (\frac{3}{5}) + 2 πn

θ = arcsin (\frac{3}{5}) + 2 πn, θ = π - arcsin (\frac{3}{5}) + 2 πn

Solutions for the range

sin (2 θ)

No Solution for θ \in R

x, \frac{1}{6} = cos^{2} (x)

tan (x) + ∣ tan (x) ∣ = 1, - 2 π \leq, x \leq 2 π

2 sin^{2} (x) + 3 sin (x) = 1

11.33 = 1.59 cos (0.9 9^{\circ} (x - 18 2^{\circ})) + 12.14

6 cos (3 x) = 6 cos (x)

What is the general solution for sin(θ)= 3/5 ,sin(2θ) ?
The general solution for sin(θ)= 3/5 ,sin(2θ) is No Solution for θ\in\mathbb{R}