What is the general solution for 0=8tan(θ) ?

The general solution for 0=8tan(θ) is θ=pin

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0=8tan(θ)

0 = 8 tan (θ)

θ = πn

Degrees

θ = 0^{\circ} + 18 0^{\circ} n

Solution steps

0 = 8 tan (θ)

Switch sides

8 tan (θ) = 0

Divide both sides by

8

8 tan (θ) = 0

Divide both sides by

8

\frac{8 tan ( θ )}{8} = \frac{0}{8}

Simplify

tan (θ) = 0

tan (θ) = 0

General solutions for

tan (θ) = 0

tan (x)

periodicity table with

πn

cycle:

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} tan (x) 0 \frac{3}{3} 13 \pm \infty - 3 - 1 - \frac{3}{3}

θ = 0 + πn

θ = 0 + πn

Solve

θ = 0 + πn : θ = πn

θ = 0 + πn

0 + πn = πn

θ = πn

θ = πn

1 = 4 sin^{2} (θ)

θ, 1 = sin (θ)

tan (2 x) = 2

\frac{sin ( b )}{13.1} = \frac{sin ( 112. 1 ^{\circ} )}{24.1}

tan (α) = \frac{0.006}{π \cdot 0.027}

What is the general solution for 0=8tan(θ) ?
The general solution for 0=8tan(θ) is θ=pin