What is the general solution for cos(θ)= 2/3 ,(sin(θ))/2 ,270<θ<360 ?

The general solution for cos(θ)= 2/3 ,(sin(θ))/2 ,270<θ<360 is No Solution for θ\in\mathbb{R}

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cos(θ)= 2/3 ,(sin(θ))/2 ,270<θ<360

cos (θ) = \frac{2}{3}, \frac{sin ( θ )}{2}, 27 0^{\circ} < θ < 36 0^{\circ}

No Solution for θ \in R

Solution steps

cos (θ) = \frac{2}{3}, \frac{sin ( θ )}{2}, 27 0^{\circ} < θ < 36 0^{\circ}

Apply trig inverse properties

cos (θ) = \frac{2}{3}

General solutions for

cos (θ) = \frac{2}{3}

cos (x) = a \Rightarrow x = arccos (a) + 2 πn, x = 2 π - arccos (a) + 2 πn

θ = arccos (\frac{2}{3}) + 2 πn, θ = 2 π - arccos (\frac{2}{3}) + 2 πn

θ = arccos (\frac{2}{3}) + 2 πn, θ = 2 π - arccos (\frac{2}{3}) + 2 πn

Solutions for the range

\frac{sin ( θ )}{2}

No Solution for θ \in R

cos (9 x) = 0

2 cos^{3} (x) - 3 sin^{2} (x) cos (x) = 0

5 cot (θ) = - 6

cos (3 x - 9 x) = 0

7 sin^{2} (θ) + 15 sin (θ) + 8 = 0

What is the general solution for cos(θ)= 2/3 ,(sin(θ))/2 ,270<θ<360 ?
The general solution for cos(θ)= 2/3 ,(sin(θ))/2 ,270<θ<360 is No Solution for θ\in\mathbb{R}