What is the general solution for cos(θ)=(5/(sqrt(29))) ?

The general solution for cos(θ)=(5/(sqrt(29))) is θ=0.38050…+2pin,θ=2pi-0.38050…+2pin

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cos(θ)=(5/(sqrt(29)))

cos (θ) = (\frac{5}{29})

θ = 0.38050 \dots + 2 πn, θ = 2 π - 0.38050 \dots + 2 πn

Radians

θ = 0.38050 \dots + 6.28318 \dots n, θ = 5.90267 \dots + 6.28318 \dots n

Solution steps

cos (θ) = (\frac{5}{29})

Simplify

\frac{5}{29} : \frac{5 29}{29}

\frac{5}{29}

Multiply by the conjugate

\frac{29}{29}

= \frac{5 29}{29 29}

2929 = 29

2929

Apply radical rule:

a a = a

2929 = 29

= 29

= \frac{5 29}{29}

cos (θ) = \frac{5 29}{29}

Apply trig inverse properties

cos (θ) = \frac{5 29}{29}

General solutions for

cos (θ) = \frac{5 29}{29}

cos (x) = a \Rightarrow x = arccos (a) + 2 πn, x = 2 π - arccos (a) + 2 πn

θ = arccos (\frac{5 29}{29}) + 2 πn, θ = 2 π - arccos (\frac{5 29}{29}) + 2 πn

θ = arccos (\frac{5 29}{29}) + 2 πn, θ = 2 π - arccos (\frac{5 29}{29}) + 2 πn

Show solutions in decimal form

θ = 0.38050 \dots + 2 πn, θ = 2 π - 0.38050 \dots + 2 πn

sin (θ) = \frac{7.5}{6.5}

cos^{2} (x) - \frac{3}{2} = \frac{5}{2} cos (x)

θ, w = fd cos (θ)

sec (x) - sec (x) tan (x) = 0

4 sin^{2} (x) = 3, 0 \leq x \leq 18 0^{\circ}

What is the general solution for cos(θ)=(5/(sqrt(29))) ?
The general solution for cos(θ)=(5/(sqrt(29))) is θ=0.38050…+2pin,θ=2pi-0.38050…+2pin