What is the general solution for sin(θ)=m ?

The general solution for sin(θ)=m is θ=arcsin(m)+2pin,θ=pi+arcsin(-m)+2pin

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sin(θ)=m

sin (θ) = m

θ = arcsin (m) + 2 πn, θ = π + arcsin (- m) + 2 πn

Solution steps

sin (θ) = m

Apply trig inverse properties

sin (θ) = m

General solutions for

sin (θ) = m

sin (x) = a \Rightarrow x = arcsin (a) + 2 πn, x = π + arcsin (a) + 2 πn

θ = arcsin (m) + 2 πn, θ = π + arcsin (- m) + 2 πn

θ = arcsin (m) + 2 πn, θ = π + arcsin (- m) + 2 πn

sin (θ) = \frac{3}{2}, cos (θ) < 0, 0 < θ < 2 π

tan (x) = 1, 0 \leq x < 2 π

x, sin (2 x) \cdot cos (2 x) = 0.5

2 sin^{2} (x) + sin (x) - 3 = 0, 6

(1 - sin (2 x)) \cdot (1 - cos^{2} (x)) = 0

What is the general solution for sin(θ)=m ?
The general solution for sin(θ)=m is θ=arcsin(m)+2pin,θ=pi+arcsin(-m)+2pin