What is the general solution for tan(θ)+3=0 ?

The general solution for tan(θ)+3=0 is θ=-1.24904…+pin

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tan(θ)+3=0

tan (θ) + 3 = 0

θ = - 1.24904 \dots + πn

Degrees

θ = - 71.56505 \dots^{\circ} + 18 0^{\circ} n

Solution steps

tan (θ) + 3 = 0

Move

3

to the right side

tan (θ) + 3 = 0

Subtract

3

from both sides

tan (θ) + 3 - 3 = 0 - 3

Simplify

tan (θ) = - 3

tan (θ) = - 3

Apply trig inverse properties

tan (θ) = - 3

General solutions for

tan (θ) = - 3

tan (x) = - a \Rightarrow x = arctan (- a) + πn

θ = arctan (- 3) + πn

θ = arctan (- 3) + πn

Show solutions in decimal form

θ = - 1.24904 \dots + πn

cos (2 x) - 4 cos (x) + 3 = 0

6 cos^{2} (A) - 5 cos (A) + 1 = 0

cos (x) tan^{2} (x) - 3 cos (x) = 0

2 sin (x) + 3 cot (x) - 3 csc (x) = 0

cos^{2} (θ) - 3 cos (θ) + 2 = 0

What is the general solution for tan(θ)+3=0 ?
The general solution for tan(θ)+3=0 is θ=-1.24904…+pin