What is the general solution for cos(θ)=0.6015 ?

The general solution for cos(θ)=0.6015 is θ=0.92541…+2pin,θ=2pi-0.92541…+2pin

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cos(θ)=0.6015

cos (θ) = 0.6015

θ = 0.92541 \dots + 2 πn, θ = 2 π - 0.92541 \dots + 2 πn

Degrees

θ = 53.02259 \dots^{\circ} + 36 0^{\circ} n, θ = 306.97740 \dots^{\circ} + 36 0^{\circ} n

Solution steps

cos (θ) = 0.6015

Apply trig inverse properties

cos (θ) = 0.6015

General solutions for

cos (θ) = 0.6015

cos (x) = a \Rightarrow x = arccos (a) + 2 πn, x = 2 π - arccos (a) + 2 πn

θ = arccos (0.6015) + 2 πn, θ = 2 π - arccos (0.6015) + 2 πn

θ = arccos (0.6015) + 2 πn, θ = 2 π - arccos (0.6015) + 2 πn

Show solutions in decimal form

θ = 0.92541 \dots + 2 πn, θ = 2 π - 0.92541 \dots + 2 πn

sin (θ) = \frac{- 4}{5}

θ, x = 5 sec (θ)

sec (3 x) - cos (3 0^{\circ}) = 0, \frac{x + 35}{5}

- 2 sin (x) + 3 = 0

sin (θ) = \frac{4}{5}, cos (θ) = \frac{3}{5}

What is the general solution for cos(θ)=0.6015 ?
The general solution for cos(θ)=0.6015 is θ=0.92541…+2pin,θ=2pi-0.92541…+2pin