What is the general solution for 4+4sin(x)=0 ?

The general solution for 4+4sin(x)=0 is x=(3pi)/2+2pin

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4+4sin(x)=0

4 + 4 sin (x) = 0

x = \frac{3 π}{2} + 2 πn

Degrees

x = 27 0^{\circ} + 36 0^{\circ} n

Solution steps

4 + 4 sin (x) = 0

Move

4

to the right side

4 + 4 sin (x) = 0

Subtract

4

from both sides

4 + 4 sin (x) - 4 = 0 - 4

Simplify

4 sin (x) = - 4

4 sin (x) = - 4

Divide both sides by

4

4 sin (x) = - 4

Divide both sides by

4

\frac{4 sin ( x )}{4} = \frac{- 4}{4}

Simplify

sin (x) = - 1

sin (x) = - 1

General solutions for

sin (x) = - 1

sin (x)

periodicity table with

2 πn

cycle:

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} sin (x) 0 \frac{1}{2} \frac{2}{2} \frac{3}{2} 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} x π \frac{7 π}{6} \frac{5 π}{4} \frac{4 π}{3} \frac{3 π}{2} \frac{5 π}{3} \frac{7 π}{4} \frac{11 π}{6} sin (x) 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2}

x = \frac{3 π}{2} + 2 πn

x = \frac{3 π}{2} + 2 πn

tan (A) = \frac{67}{94}

sin (8 x) - 2 cos (4 x) = 0

1.812 = 316 \cdot cos (1.496 \cdot x) + 1.496

t, cos (wt + d) = 0

sin (θ) = 3 cos (θ), 0 \leq θ < 2 π

What is the general solution for 4+4sin(x)=0 ?
The general solution for 4+4sin(x)=0 is x=(3pi)/2+2pin