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0=4cos(x)sin(x)-sin(x)

الحلّ

0 = 4 cos (x) sin (x) - sin (x)

الحلّ

x = 2 πn, x = π + 2 πn, x = 1.31811 \dots + 2 πn, x = 2 π - 1.31811 \dots + 2 πn

+1

درجات

x = 0^{\circ} + 36 0^{\circ} n, x = 18 0^{\circ} + 36 0^{\circ} n, x = 75.52248 \dots^{\circ} + 36 0^{\circ} n, x = 284.47751 \dots^{\circ} + 36 0^{\circ} n

خطوات الحلّ

0 = 4 cos (x) sin (x) - sin (x)

بدّل الأطراف

4 cos (x) sin (x) - sin (x) = 0

4 cos (x) sin (x) - sin (x)

حلل إلى عوامل:

sin (x) (4 cos (x) - 1)

4 cos (x) sin (x) - sin (x)

sin (x)

قم باخراج العامل المشترك

= sin (x) (4 cos (x) - 1)

sin (x) (4 cos (x) - 1) = 0

حلّ كل جزء على حدة

sin (x) = 0 or 4 cos (x) - 1 = 0

sin (x) = 0 : x = 2 πn, x = π + 2 πn

sin (x) = 0

sin (x) = 0 :

حلول عامّة لـ

sin (x)

periodicity table with

2 πn

cycle:

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} sin (x) 0 \frac{1}{2} \frac{2}{2} \frac{3}{2} 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} x π \frac{7 π}{6} \frac{5 π}{4} \frac{4 π}{3} \frac{3 π}{2} \frac{5 π}{3} \frac{7 π}{4} \frac{11 π}{6} sin (x) 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2}

x = 0 + 2 πn, x = π + 2 πn

x = 0 + 2 πn, x = π + 2 πn

x = 0 + 2 πn

حلّ:

x = 2 πn

x = 0 + 2 πn

0 + 2 πn = 2 πn

x = 2 πn

x = 2 πn, x = π + 2 πn

4 cos (x) - 1 = 0 : x = arccos (\frac{1}{4}) + 2 πn, x = 2 π - arccos (\frac{1}{4}) + 2 πn

4 cos (x) - 1 = 0

انقل

1

إلى الجانب الأيمن

4 cos (x) - 1 = 0

للطرفين

1

أضف

4 cos (x) - 1 + 1 = 0 + 1

بسّط

4 cos (x) = 1

4 cos (x) = 1

4

اقسم الطرفين على

4 cos (x) = 1

4

اقسم الطرفين على

\frac{4 cos ( x )}{4} = \frac{1}{4}

بسّط

cos (x) = \frac{1}{4}

cos (x) = \frac{1}{4}

Apply trig inverse properties

cos (x) = \frac{1}{4}

cos (x) = \frac{1}{4} :

حلول عامّة لـ

cos (x) = a \Rightarrow x = arccos (a) + 2 πn, x = 2 π - arccos (a) + 2 πn

x = arccos (\frac{1}{4}) + 2 πn, x = 2 π - arccos (\frac{1}{4}) + 2 πn

x = arccos (\frac{1}{4}) + 2 πn, x = 2 π - arccos (\frac{1}{4}) + 2 πn

وحّد الحلول

x = 2 πn, x = π + 2 πn, x = arccos (\frac{1}{4}) + 2 πn, x = 2 π - arccos (\frac{1}{4}) + 2 πn

أظهر الحلّ بالتمثيل العشريّ

x = 2 πn, x = π + 2 πn, x = 1.31811 \dots + 2 πn, x = 2 π - 1.31811 \dots + 2 πn

أمثلة شائعة

sin(x)cos(x)=tan(x)

sin (x) cos (x) = tan (x)

cos(x)=(sqrt(2))/4

cos (x) = \frac{2}{4}

sin(x)-sin(x)*cos(x)=0

sin (x) - sin (x) \cdot cos (x) = 0

1-1tan^2(2x)=sec^2(2x)

1 - 1 tan^{2} (2 x) = sec^{2} (2 x)

10tan(θ)-4.9((10)/(13cos(θ)))^2=0

10 tan (θ) - 4.9 (\frac{10}{13 cos ( θ )})^{2} = 0