What is the general solution for 2sin(v)csc(v)-csc(v)=4sin(v)-2 ?

The general solution for 2sin(v)csc(v)-csc(v)=4sin(v)-2 is v= pi/6+2pin,v=(5pi)/6+2pin

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2sin(v)csc(v)-csc(v)=4sin(v)-2

Solution

2 sin (v) csc (v) - csc (v) = 4 sin (v) - 2

Solution

v = \frac{π}{6} + 2 πn, v = \frac{5 π}{6} + 2 πn

Degrees

v = 3 0^{\circ} + 36 0^{\circ} n, v = 15 0^{\circ} + 36 0^{\circ} n

Solution steps

2 sin (v) csc (v) - csc (v) = 4 sin (v) - 2

Subtract

4 sin (v) - 2

from both sides

2 sin (v) csc (v) - csc (v) - 4 sin (v) + 2 = 0

Factor

2 sin (v) csc (v) - csc (v) - 4 sin (v) + 2 : (2 sin (v) - 1) (csc (v) - 2)

2 sin (v) csc (v) - csc (v) - 4 sin (v) + 2

= (2 sin (v) csc (v) - csc (v)) + (- 4 sin (v) + 2)

Factor out

- 2

from

- 4 sin (v) + 2 : - 2 (2 sin (v) - 1)

- 4 sin (v) + 2

Rewrite

- 4

2 \cdot 2

= 2 \cdot 2 sin (v) + 2

Factor out common term

- 2

= - 2 (2 sin (v) - 1)

Factor out

csc (v)

from

2 sin (v) csc (v) - csc (v) : csc (v) (2 sin (v) - 1)

2 sin (v) csc (v) - csc (v)

Factor out common term

csc (v)

= csc (v) (2 sin (v) - 1)

= - 2 (2 sin (v) - 1) + csc (v) (2 sin (v) - 1)

Factor out common term

2 sin (v) - 1

= (2 sin (v) - 1) (csc (v) - 2)

(2 sin (v) - 1) (csc (v) - 2) = 0

Solving each part separately

2 sin (v) - 1 = 0 or csc (v) - 2 = 0

2 sin (v) - 1 = 0 : v = \frac{π}{6} + 2 πn, v = \frac{5 π}{6} + 2 πn

2 sin (v) - 1 = 0

Move

1

to the right side

2 sin (v) - 1 = 0

Add

1

to both sides

2 sin (v) - 1 + 1 = 0 + 1

Simplify

2 sin (v) = 1

2 sin (v) = 1

Divide both sides by

2

2 sin (v) = 1

Divide both sides by

2

\frac{2 sin ( v )}{2} = \frac{1}{2}

Simplify

sin (v) = \frac{1}{2}

sin (v) = \frac{1}{2}

General solutions for

sin (v) = \frac{1}{2}

sin (x)

periodicity table with

2 πn

cycle:

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} sin (x) 0 \frac{1}{2} \frac{2}{2} \frac{3}{2} 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} x π \frac{7 π}{6} \frac{5 π}{4} \frac{4 π}{3} \frac{3 π}{2} \frac{5 π}{3} \frac{7 π}{4} \frac{11 π}{6} sin (x) 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2}

v = \frac{π}{6} + 2 πn, v = \frac{5 π}{6} + 2 πn

v = \frac{π}{6} + 2 πn, v = \frac{5 π}{6} + 2 πn

csc (v) - 2 = 0 : v = \frac{π}{6} + 2 πn, v = \frac{5 π}{6} + 2 πn

csc (v) - 2 = 0

Move

2

to the right side

csc (v) - 2 = 0

Add

2

to both sides

csc (v) - 2 + 2 = 0 + 2

Simplify

csc (v) = 2

csc (v) = 2

General solutions for

csc (v) = 2

csc (x)

periodicity table with

2 πn

cycle:

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} csc (x) Undefiend 22 \frac{2 3}{3} 1 \frac{2 3}{3} 22 x π \frac{7 π}{6} \frac{5 π}{4} \frac{4 π}{3} \frac{3 π}{2} \frac{5 π}{3} \frac{7 π}{4} \frac{11 π}{6} csc (x) Undefiend - 2 - 2 - \frac{2 3}{3} - 1 - \frac{2 3}{3} - 2 - 2

v = \frac{π}{6} + 2 πn, v = \frac{5 π}{6} + 2 πn

v = \frac{π}{6} + 2 πn, v = \frac{5 π}{6} + 2 πn

Combine all the solutions

v = \frac{π}{6} + 2 πn, v = \frac{5 π}{6} + 2 πn

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Frequently Asked Questions (FAQ)

What is the general solution for 2sin(v)csc(v)-csc(v)=4sin(v)-2 ?
The general solution for 2sin(v)csc(v)-csc(v)=4sin(v)-2 is v= pi/6+2pin,v=(5pi)/6+2pin