What is the general solution for 28cos(t)=20,0<= t<360 ?

The general solution for 28cos(t)=20,0<= t<360 is t=0.77519…,t=360-0.77519…

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28cos(t)=20,0<= t<360

28 cos (t) = 20, 0^{\circ} \leq t < 36 0^{\circ}

t = 0.77519 \dots, t = 36 0^{\circ} - 0.77519 \dots

Radians

t = 0.77519 \dots, t = 2 π - 0.77519 \dots

Solution steps

28 cos (t) = 20, 0^{\circ} \leq t < 36 0^{\circ}

Divide both sides by

28

28 cos (t) = 20

Divide both sides by

28

\frac{28 cos ( t )}{28} = \frac{20}{28}

Simplify

cos (t) = \frac{5}{7}

cos (t) = \frac{5}{7}

Apply trig inverse properties

cos (t) = \frac{5}{7}

General solutions for

cos (t) = \frac{5}{7}

cos (x) = a \Rightarrow x = arccos (a) + 36 0^{\circ} n, x = 36 0^{\circ} - arccos (a) + 36 0^{\circ} n

t = arccos (\frac{5}{7}) + 36 0^{\circ} n, t = 36 0^{\circ} - arccos (\frac{5}{7}) + 36 0^{\circ} n

t = arccos (\frac{5}{7}) + 36 0^{\circ} n, t = 36 0^{\circ} - arccos (\frac{5}{7}) + 36 0^{\circ} n

Solutions for the range

0 \leq t < 36 0^{\circ}

t = arccos (\frac{5}{7}), t = 36 0^{\circ} - arccos (\frac{5}{7})

Show solutions in decimal form

t = 0.77519 \dots, t = 36 0^{\circ} - 0.77519 \dots

8 tan (\frac{x}{2}) + 8 cos (x) tan (\frac{x}{2}) = 1

sin (a) = 0.5937

tan (x) = \frac{18}{25}

sin^{2} (x) = \frac{3}{2}

1.5 = 1 + sin (\frac{x}{3})

What is the general solution for 28cos(t)=20,0<= t<360 ?
The general solution for 28cos(t)=20,0<= t<360 is t=0.77519…,t=360-0.77519…