What is the general solution for 1-cos(x)=2 ?

The general solution for 1-cos(x)=2 is x=pi+2pin

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

1-cos(x)=2

1 - cos (x) = 2

x = π + 2 πn

Degrees

x = 18 0^{\circ} + 36 0^{\circ} n

Solution steps

1 - cos (x) = 2

Move

1

to the right side

1 - cos (x) = 2

Subtract

1

from both sides

1 - cos (x) - 1 = 2 - 1

Simplify

- cos (x) = 1

- cos (x) = 1

Divide both sides by

- 1

- cos (x) = 1

Divide both sides by

- 1

\frac{- cos ( x )}{- 1} = \frac{1}{- 1}

Simplify

cos (x) = - 1

cos (x) = - 1

General solutions for

cos (x) = - 1

cos (x)

periodicity table with

2 πn

cycle:

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} cos (x) 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} x π \frac{7 π}{6} \frac{5 π}{4} \frac{4 π}{3} \frac{3 π}{2} \frac{5 π}{3} \frac{7 π}{4} \frac{11 π}{6} cos (x) - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2} 0 \frac{1}{2} \frac{2}{2} \frac{3}{2}

x = π + 2 πn

x = π + 2 πn

8 sin^{2} (x) + 6 cos^{2} (x) = 10

sin^{2} (9 0^{\circ} - b) + cos^{2} (b - 45 0^{\circ}) = 1

cos^{2} (2 x) + sin^{2} (x) = 1

cos^{2} (x) = \frac{1 - tan ^{2} ( x )}{sec ^{2} ( x )}

sin^{2} (x) - 3 cos (x) - 4 = 0

What is the general solution for 1-cos(x)=2 ?
The general solution for 1-cos(x)=2 is x=pi+2pin