What is the general solution for sin(-t)= 3/10 ?

The general solution for sin(-t)= 3/10 is t=-0.30469…-2pin,t=-pi+0.30469…-2pin

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Popular >

sin(-t)= 3/10

Solution

sin (- t) = \frac{3}{10}

Solution

t = - 0.30469 \dots - 2 πn, t = - π + 0.30469 \dots - 2 πn

Degrees

t = - 17.45760 \dots^{\circ} - 36 0^{\circ} n, t = - 162.54239 \dots^{\circ} - 36 0^{\circ} n

Solution steps

sin (- t) = \frac{3}{10}

Apply trig inverse properties

sin (- t) = \frac{3}{10}

General solutions for

sin (- t) = \frac{3}{10}

sin (x) = a \Rightarrow x = arcsin (a) + 2 πn, x = π - arcsin (a) + 2 πn

- t = arcsin (\frac{3}{10}) + 2 πn, - t = π - arcsin (\frac{3}{10}) + 2 πn

- t = arcsin (\frac{3}{10}) + 2 πn, - t = π - arcsin (\frac{3}{10}) + 2 πn

Solve

- t = arcsin (\frac{3}{10}) + 2 πn : t = - arcsin (\frac{3}{10}) - 2 πn

- t = arcsin (\frac{3}{10}) + 2 πn

Divide both sides by

- 1

- t = arcsin (\frac{3}{10}) + 2 πn

Divide both sides by

- 1

\frac{- t}{- 1} = \frac{arcsin ( \frac{3}{10} )}{- 1} + \frac{2 πn}{- 1}

Simplify

\frac{- t}{- 1} = \frac{arcsin ( \frac{3}{10} )}{- 1} + \frac{2 πn}{- 1}

Simplify

\frac{- t}{- 1} : t

\frac{- t}{- 1}

Apply the fraction rule:

\frac{- a}{- b} = \frac{a}{b}

= \frac{t}{1}

Apply rule

\frac{a}{1} = a

= t

Simplify

\frac{arcsin ( \frac{3}{10} )}{- 1} + \frac{2 πn}{- 1} : - arcsin (\frac{3}{10}) - 2 πn

\frac{arcsin ( \frac{3}{10} )}{- 1} + \frac{2 πn}{- 1}

\frac{arcsin ( \frac{3}{10} )}{- 1} = - arcsin (\frac{3}{10})

\frac{arcsin ( \frac{3}{10} )}{- 1}

Apply the fraction rule:

\frac{a}{- b} = - \frac{a}{b}

= - \frac{arcsin ( \frac{3}{10} )}{1}

Apply the fraction rule:

\frac{a}{1} = a

\frac{arcsin ( \frac{3}{10} )}{1} = arcsin (\frac{3}{10})

= - arcsin (\frac{3}{10})

= - arcsin (\frac{3}{10}) + \frac{2 πn}{- 1}

\frac{2 πn}{- 1} = - 2 πn

\frac{2 πn}{- 1}

Apply the fraction rule:

\frac{a}{- b} = - \frac{a}{b}

= - \frac{2 πn}{1}

Apply rule

\frac{a}{1} = a

= - 2 πn

= - arcsin (\frac{3}{10}) - 2 πn

t = - arcsin (\frac{3}{10}) - 2 πn

t = - arcsin (\frac{3}{10}) - 2 πn

t = - arcsin (\frac{3}{10}) - 2 πn

Solve

- t = π - arcsin (\frac{3}{10}) + 2 πn : t = - π + arcsin (\frac{3}{10}) - 2 πn

- t = π - arcsin (\frac{3}{10}) + 2 πn

Divide both sides by

- 1

- t = π - arcsin (\frac{3}{10}) + 2 πn

Divide both sides by

- 1

\frac{- t}{- 1} = \frac{π}{- 1} - \frac{arcsin ( \frac{3}{10} )}{- 1} + \frac{2 πn}{- 1}

Simplify

\frac{- t}{- 1} = \frac{π}{- 1} - \frac{arcsin ( \frac{3}{10} )}{- 1} + \frac{2 πn}{- 1}

Simplify

\frac{- t}{- 1} : t

\frac{- t}{- 1}

Apply the fraction rule:

\frac{- a}{- b} = \frac{a}{b}

= \frac{t}{1}

Apply rule

\frac{a}{1} = a

= t

Simplify

\frac{π}{- 1} - \frac{arcsin ( \frac{3}{10} )}{- 1} + \frac{2 πn}{- 1} : - π + arcsin (\frac{3}{10}) - 2 πn

\frac{π}{- 1} - \frac{arcsin ( \frac{3}{10} )}{- 1} + \frac{2 πn}{- 1}

\frac{π}{- 1} = - π

\frac{π}{- 1}

Apply the fraction rule:

\frac{a}{- b} = - \frac{a}{b}

= - \frac{π}{1}

Apply rule

\frac{a}{1} = a

= - π

= - π - \frac{arcsin ( \frac{3}{10} )}{- 1} + \frac{2 πn}{- 1}

\frac{arcsin ( \frac{3}{10} )}{- 1} = - arcsin (\frac{3}{10})

\frac{arcsin ( \frac{3}{10} )}{- 1}

Apply the fraction rule:

\frac{a}{- b} = - \frac{a}{b}

= - \frac{arcsin ( \frac{3}{10} )}{1}

Apply the fraction rule:

\frac{a}{1} = a

\frac{arcsin ( \frac{3}{10} )}{1} = arcsin (\frac{3}{10})

= - arcsin (\frac{3}{10})

\frac{2 πn}{- 1} = - 2 πn

\frac{2 πn}{- 1}

Apply the fraction rule:

\frac{a}{- b} = - \frac{a}{b}

= - \frac{2 πn}{1}

Apply rule

\frac{a}{1} = a

= - 2 πn

= - π - (- arcsin (\frac{3}{10})) - 2 πn

Apply rule

- (- a) = a

= - π + arcsin (\frac{3}{10}) - 2 πn

t = - π + arcsin (\frac{3}{10}) - 2 πn

t = - π + arcsin (\frac{3}{10}) - 2 πn

t = - π + arcsin (\frac{3}{10}) - 2 πn

t = - arcsin (\frac{3}{10}) - 2 πn, t = - π + arcsin (\frac{3}{10}) - 2 πn

Show solutions in decimal form

t = - 0.30469 \dots - 2 πn, t = - π + 0.30469 \dots - 2 πn

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Frequently Asked Questions (FAQ)

What is the general solution for sin(-t)= 3/10 ?
The general solution for sin(-t)= 3/10 is t=-0.30469…-2pin,t=-pi+0.30469…-2pin