What is the general solution for y=2sin(cos(+0)) ?

The general solution for y=2sin(cos(+0)) is y=2sin(1)

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y=2sin(cos(+0))

y = 2 sin (cos (+ 0))

y = 2 sin (1)

Decimal Notation

y = 1.68294 \dots

Solution steps

y = 2 sin (cos (0))

Simplify

cos (0) : 1

cos (0)

Use the following trivial identity:

cos (0) = 1

cos (x)

periodicity table with

2 πn

cycle:

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} cos (x) 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} x π \frac{7 π}{6} \frac{5 π}{4} \frac{4 π}{3} \frac{3 π}{2} \frac{5 π}{3} \frac{7 π}{4} \frac{11 π}{6} cos (x) - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2} 0 \frac{1}{2} \frac{2}{2} \frac{3}{2}

= 1

y = 2 sin (1)

x, y = x + 2 arctan (p)

x, z = sin (x) + cos^{3} (y)

r = 1 - sin (0)

x, sin^{2} (y) + cos (x) y = k

c, cos (x) - cos^{2} (x) = sin^{3} (x)

What is the general solution for y=2sin(cos(+0)) ?
The general solution for y=2sin(cos(+0)) is y=2sin(1)