What is the general solution for solvefor t,cot(90^0+x)=tan(x) ?

The general solution for solvefor t,cot(90^0+x)=tan(x) is True for all t;\quad cot(1+x)=tan(x)

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solvefor t,cot(90^0+x)=tan(x)

solve for

t, cot (9 0^{0} + x) = tan (x)

True for all t; cot (1 + x) = tan (x)

Solution steps

cot (9 0^{0} + x) = tan (x)

Simplify

cot (9 0^{0} + x) : cot (1 + x)

cot (9 0^{0} + x)

Apply rule

a^{0} = 1, a \neq = 0

9 0^{0} = 1

= cot (1 + x)

cot (1 + x) = tan (x)

Both sides are equal

True for all t; cot (1 + x) = tan (x)

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x, y = cos (\frac{y}{1.75}) + x - 0.5 y^{2}

c, 2 sin^{3} (x) + cos^{2} (x) - cos (x) = 0

i, sin (x^{2}) + cos^{2} (x) + sin (x) + 1 = 0

t, tan^{2} (x) cot (x) = 1 + sec^{2} (x)

What is the general solution for solvefor t,cot(90^0+x)=tan(x) ?
The general solution for solvefor t,cot(90^0+x)=tan(x) is True for all t;\quad cot(1+x)=tan(x)