What is the general solution for 2x=sin(90) ?

The general solution for 2x=sin(90) is x= 1/2

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2x=sin(90)

2 x = sin (9 0^{\circ})

x = \frac{1}{2}

Decimal Notation

x = 0.5

Solution steps

2 x = sin (9 0^{\circ})

Simplify

sin (9 0^{\circ}) : 1

sin (9 0^{\circ})

Use the following trivial identity:

sin (9 0^{\circ}) = 1

sin (x)

periodicity table with

36 0^{\circ} n

cycle:

x 0 3 0^{\circ} 4 5^{\circ} 6 0^{\circ} 9 0^{\circ} 12 0^{\circ} 13 5^{\circ} 15 0^{\circ} sin (x) 0 \frac{1}{2} \frac{2}{2} \frac{3}{2} 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} x 18 0^{\circ} 21 0^{\circ} 22 5^{\circ} 24 0^{\circ} 27 0^{\circ} 30 0^{\circ} 31 5^{\circ} 33 0^{\circ} sin (x) 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2}

= 1

2 x = 1

Divide both sides by

2

2 x = 1

Divide both sides by

2

\frac{2 x}{2} = \frac{1}{2}

Simplify

x = \frac{1}{2}

x = \frac{1}{2}

c, 10 cos (x) - 24 sin (2 x) = 13

y, d^{2} - 4 d + 4 y = e^{2} x + x^{2} + x + sin^{2} (x)

y, (d^{2} - 5 d + 6) \cdot y = x + sin^{3} (x)

t, cot (x) sin^{2} (x) = 1 + cos^{2} (x)

f, (6) f = t^{s i n (t)}

What is the general solution for 2x=sin(90) ?
The general solution for 2x=sin(90) is x= 1/2