What is the general solution for solvefor a,sin(0)= a/h ?

The general solution for solvefor a,sin(0)= a/h is a=0

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solvefor a,sin(0)= a/h

solve for

a, sin (0) = \frac{a}{h}

a = 0

Solution steps

sin (0) = \frac{a}{h}

Switch sides

\frac{a}{h} = sin (0)

Simplify

sin (0) : 0

sin (0)

Use the following trivial identity:

sin (0) = 0

sin (x)

periodicity table with

2 πn

cycle:

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} sin (x) 0 \frac{1}{2} \frac{2}{2} \frac{3}{2} 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} x π \frac{7 π}{6} \frac{5 π}{4} \frac{4 π}{3} \frac{3 π}{2} \frac{5 π}{3} \frac{7 π}{4} \frac{11 π}{6} sin (x) 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2}

= 0

\frac{a}{h} = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

a = 0

c, 1 - sin^{2} (x) = 4 cos (x) - 4 sin (x)

y, (x^{2} \cdot d^{2} + x \cdot d - 1) y = sin (lo g_{10} (x^{2}))

c, sin^{2} (x) + 2 (sin (x) + cos (x)) - 3 = 0

sin (3 0^{\circ}) = \frac{x}{1}

i, sin (x) + sin^{2} (x) + cos^{3} (x) = 1

What is the general solution for solvefor a,sin(0)= a/h ?
The general solution for solvefor a,sin(0)= a/h is a=0