What is the general solution for csc(θ)-sqrt(2)=0 ?

The general solution for csc(θ)-sqrt(2)=0 is θ= pi/4+2pin,θ=(3pi)/4+2pin

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

csc(θ)-sqrt(2)=0

csc (θ) - 2 = 0

θ = \frac{π}{4} + 2 πn, θ = \frac{3 π}{4} + 2 πn

Degrees

θ = 4 5^{\circ} + 36 0^{\circ} n, θ = 13 5^{\circ} + 36 0^{\circ} n

Solution steps

csc (θ) - 2 = 0

Move

2

to the right side

csc (θ) - 2 = 0

Add

2

to both sides

csc (θ) - 2 + 2 = 0 + 2

Simplify

csc (θ) = 2

csc (θ) = 2

General solutions for

csc (θ) = 2

csc (x)

periodicity table with

2 πn

cycle:

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} csc (x) Undefiend 22 \frac{2 3}{3} 1 \frac{2 3}{3} 22 x π \frac{7 π}{6} \frac{5 π}{4} \frac{4 π}{3} \frac{3 π}{2} \frac{5 π}{3} \frac{7 π}{4} \frac{11 π}{6} csc (x) Undefiend - 2 - 2 - \frac{2 3}{3} - 1 - \frac{2 3}{3} - 2 - 2

θ = \frac{π}{4} + 2 πn, θ = \frac{3 π}{4} + 2 πn

θ = \frac{π}{4} + 2 πn, θ = \frac{3 π}{4} + 2 πn

cot (13 5^{\circ})

tan (3)

3 csc (θ) - 2 = 0

sin (\frac{10 π}{3})

tan (\frac{2 π}{3})

What is the general solution for csc(θ)-sqrt(2)=0 ?
The general solution for csc(θ)-sqrt(2)=0 is θ= pi/4+2pin,θ=(3pi)/4+2pin