What is the general solution for sqrt(3)tan(θ)-1=0,0<= θ<= 2pi ?

The general solution for sqrt(3)tan(θ)-1=0,0<= θ<= 2pi is θ= pi/6 ,θ=(7pi)/6

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sqrt(3)tan(θ)-1=0,0<= θ<= 2pi

3 tan (θ) - 1 = 0, 0 \leq θ \leq 2 π

θ = \frac{π}{6}, θ = \frac{7 π}{6}

Solution steps

3 tan (θ) - 1 = 0, 0 \leq θ \leq 2 π

Move

1

to the right side

3 tan (θ) = 1

Divide both sides by

3

tan (θ) = \frac{3}{3}

General solutions for

tan (θ) = \frac{3}{3}

θ = \frac{π}{6} + πn

Solutions for the range

0 \leq θ \leq 2 π

θ = \frac{π}{6}, θ = \frac{7 π}{6}

- cos (\frac{π}{2})

sin^{3} (\frac{π}{2})

sin (3 θ) = 1

4 sin^{2} (x) = 3

sin (\frac{7 π}{2})

What is the general solution for sqrt(3)tan(θ)-1=0,0<= θ<= 2pi ?
The general solution for sqrt(3)tan(θ)-1=0,0<= θ<= 2pi is θ= pi/6 ,θ=(7pi)/6