What is the general solution for cos(2θ)=-(sqrt(3))/2 ?

The general solution for cos(2θ)=-(sqrt(3))/2 is θ=(5pi)/(12)+pin,θ=(7pi)/(12)+pin

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cos(2θ)=-(sqrt(3))/2

cos (2 θ) = - \frac{3}{2}

θ = \frac{5 π}{12} + πn, θ = \frac{7 π}{12} + πn

Solution steps

cos (2 θ) = - \frac{3}{2}

General solutions for

cos (2 θ) = - \frac{3}{2}

2 θ = \frac{5 π}{6} + 2 πn, 2 θ = \frac{7 π}{6} + 2 πn

Solve

2 θ = \frac{5 π}{6} + 2 πn : θ = \frac{5 π}{12} + πn

Solve

2 θ = \frac{7 π}{6} + 2 πn : θ = \frac{7 π}{12} + πn

θ = \frac{5 π}{12} + πn, θ = \frac{7 π}{12} + πn

cot^{2} (13 5^{\circ}) - sin (21 0^{\circ}) + 5 cos^{2} (22 5^{\circ})

sin (1)

2 sin^{2} (θ) = 1 - sin (θ)

sin (2 x) - sin (x) = 0

sin (54 0^{\circ})

What is the general solution for cos(2θ)=-(sqrt(3))/2 ?
The general solution for cos(2θ)=-(sqrt(3))/2 is θ=(5pi)/(12)+pin,θ=(7pi)/(12)+pin