What are the solutions to the equation 3b^2+6b+91=0 ?

The solutions to the equation 3b^2+6b+91=0 are b=-1+i(2sqrt(66))/3 ,b=-1-i(2sqrt(66))/3

Find the zeros of 3b^2+6b+91=0

The zeros of 3b^2+6b+91=0 are b=-1+i(2sqrt(66))/3 ,b=-1-i(2sqrt(66))/3

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3 b^{2} + 6 b + 91 = 0

b = - 1 + i \frac{2 66}{3}, b = - 1 - i \frac{2 66}{3}

Solution steps

3 b^{2} + 6 b + 91 = 0

Solve with the quadratic formula

b_{1, 2} = \frac{- 6 \pm 6 ^{2} - 4 \cdot 3 \cdot 91}{2 \cdot 3}

Simplify

6^{2} - 4 \cdot 3 \cdot 91 : 466 i

b_{1, 2} = \frac{- 6 \pm 4 66 i}{2 \cdot 3}

Separate the solutions

b_{1} = \frac{- 6 + 4 66 i}{2 \cdot 3}, b_{2} = \frac{- 6 - 4 66 i}{2 \cdot 3}

b = \frac{- 6 + 4 66 i}{2 \cdot 3} : - 1 + i \frac{2 66}{3}

b = \frac{- 6 - 4 66 i}{2 \cdot 3} : - 1 - i \frac{2 66}{3}

The solutions to the quadratic equation are:

b = - 1 + i \frac{2 66}{3}, b = - 1 - i \frac{2 66}{3}

x^{2} - 12 x = - 11

lo g_{1} (2) = 3

\frac{12 q ^{- 3}}{( 3 p ^{4} q ^{- 3} ) ^{- 4}}

3 x^{2} - x - 2

6 x^{2} + 7 x - 20 = 0

What are the solutions to the equation 3b^2+6b+91=0 ?
The solutions to the equation 3b^2+6b+91=0 are b=-1+i(2sqrt(66))/3 ,b=-1-i(2sqrt(66))/3
Find the zeros of 3b^2+6b+91=0
The zeros of 3b^2+6b+91=0 are b=-1+i(2sqrt(66))/3 ,b=-1-i(2sqrt(66))/3