What is the derivative of-ln(-x) ?

The derivative of-ln(-x) is -1/x

What is the first derivative of-ln(-x) ?

The first derivative of-ln(-x) is -1/x

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\frac{d}{d x} (- ln (- x))

- \frac{1}{x}

Solution steps

\frac{d}{d x} (- ln (- x))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= - \frac{d}{d x} (ln (- x))

Apply the chain rule:

\frac{1}{- x} \frac{d}{d x} (- x)

= \frac{1}{- x} \frac{d}{d x} (- x)

\frac{d}{d x} (- x) = - 1

= - \frac{1}{- x} (- 1)

Simplify

= - \frac{1}{x}

f (x) = \frac{e ^{x}}{2 x + 1}

y^{^{''}} + 11 y^{^{'}} + 30 y = 0

f (x, y) = x^{2} + y^{2}

ln (16 x)

y = a^{x}