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Popular >

midpoint (-10,1),(-2,-4)

Solution

midpoint

(- 10, 1), (- 2, - 4)

Solution

(- 6, - \frac{3}{2})

Solution steps

Midpoint of

(x_{1}, y_{1}), (x_{2}, y_{2})

:

(\frac{x _{2} + x _{1}}{2}, \frac{y _{2} + y _{1}}{2})

(x_{1}, y_{1}) = (- 10, 1), (x_{2}, y_{2}) = (- 2, - 4)

= (\frac{- 2 - 10}{2}, \frac{- 4 + 1}{2})

Refine

= (- 6, - \frac{3}{2})

Popular Examples

critical xe^{-3x}critical points

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inverse of f(x)= 1/4 x^3+8 inverse

f (x) = \frac{1}{4} x^{3} + 8

asymptotes of (x-2)e^x asymptotes

(x - 2) e^{x}

inverse of f(x)= 7/(5x+7)inverse

f (x) = \frac{7}{5 x + 7}

domain of (2x^2-x-7)/(x^2+9)domain

\frac{2 x ^{2} - x - 7}{x ^{2} + 9}

Frequently Asked Questions (FAQ)

What is the midpoint (-10,1),(-2,-4) ?
The midpoint (-10,1),(-2,-4) is (-6,-3/2)