What are the solutions to the equation 2x^2=-3x ?

The solutions to the equation 2x^2=-3x are x=0,x=-3/2

Find the zeros of 2x^2=-3x

The zeros of 2x^2=-3x are x=0,x=-3/2

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2 x^{2} = - 3 x

x = 0, x = - \frac{3}{2}

Solution steps

2 x^{2} = - 3 x

Move

3 x

to the left side

2 x^{2} + 3 x = 0

Factor

2 x^{2} + 3 x : x (2 x + 3)

x (2 x + 3) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x = 0 or 2 x + 3 = 0

Solve

2 x + 3 = 0 : x = - \frac{3}{2}

The solutions to the quadratic equation are:

x = 0, x = - \frac{3}{2}

\frac{n}{3} = 2

\frac{7 n}{24 n ^{3} - 64 n ^{2}} \cdot \frac{9 n - 24}{7 n}

8^{\frac{1}{3}}

s^{2} - 27 s = 0

\frac{1}{\frac{1}{20} + \frac{1}{20}}

What are the solutions to the equation 2x^2=-3x ?
The solutions to the equation 2x^2=-3x are x=0,x=-3/2
Find the zeros of 2x^2=-3x
The zeros of 2x^2=-3x are x=0,x=-3/2