What are the solutions to the equation m^2-2m+1=0 ?

The solutions to the equation m^2-2m+1=0 are m=1

Find the zeros of m^2-2m+1=0

The zeros of m^2-2m+1=0 are m=1

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m^{2} - 2 m + 1 = 0

m = 1

Solution steps

m^{2} - 2 m + 1 = 0

Solve with the quadratic formula

m_{1, 2} = \frac{- ( - 2 ) \pm ( - 2 ) ^{2} - 4 \cdot 1 \cdot 1}{2 \cdot 1}

(- 2)^{2} - 4 \cdot 1 \cdot 1 = 0

m_{1, 2} = \frac{- ( - 2 ) \pm 0}{2 \cdot 1}

m = \frac{- ( - 2 )}{2 \cdot 1}

\frac{- ( - 2 )}{2 \cdot 1} = 1

m = 1

The solution to the quadratic equation is:

m = 1

- x^{2} + 3 x - 2

q + lo g_{2} (6) = 2 q + 2

- 4 - (- 6)

x - x^{2} = lo g_{5} (\frac{1}{25})

7 x^{2} - 14 x + 5 = - x^{2}

What are the solutions to the equation m^2-2m+1=0 ?
The solutions to the equation m^2-2m+1=0 are m=1
Find the zeros of m^2-2m+1=0
The zeros of m^2-2m+1=0 are m=1