What is -2<(4x+1)/3 <= 0 ?

The solution to -2<(4x+1)/3 <= 0 is -7/4 <x<=-1/4

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-2<(4x+1)/3 <= 0

- 2 < \frac{4 x + 1}{3} \leq 0

- \frac{7}{4} < x \leq - \frac{1}{4}

Interval Notation

(- \frac{7}{4}, - \frac{1}{4}]

Decimal Notation

- 1.75 < x \leq - 0.25

Solution steps

- 2 < \frac{4 x + 1}{3} \leq 0

a < u \leq b

then

a < u and u \leq b

- 2 < \frac{4 x + 1}{3} and \frac{4 x + 1}{3} \leq 0

- 2 < \frac{4 x + 1}{3} : x > - \frac{7}{4}

\frac{4 x + 1}{3} \leq 0 : x \leq - \frac{1}{4}

Combine the intervals

x > - \frac{7}{4} and x \leq - \frac{1}{4}

Merge Overlapping Intervals

- \frac{7}{4} < x \leq - \frac{1}{4}

8 x - 7 = 6 x + 11

8 x^{2} + 22 x + 15 = 0

v^{2} = 12 v

27 n^{2} - 54 n + 15

y^{2} (y + 5) - 16 (y + 5)