What is 12-2|x+4|>6 ?

The solution to 12-2|x+4|>6 is -7<x<-1

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12-2|x+4|>6

12 - 2 ∣ x + 4 ∣ > 6

- 7 < x < - 1

Interval Notation

(- 7, - 1)

Solution steps

12 - 2 ∣ x + 4 ∣ > 6

Move

12

to the right side

- 2 ∣ x + 4 ∣ > - 6

Multiply both sides by

- 1

2 ∣ x + 4 ∣ < 6

Divide both sides by

2

∣ x + 4 ∣ < 3

Apply absolute rule: If

∣ u ∣ < a, a > 0

then

- a < u < a

- 3 < x + 4 < 3

x + 4 > - 3 and x + 4 < 3

x > - 7 and x < - 1

Merge Overlapping Intervals

- 7 < x < - 1

x^{3} - 12 x^{2} + 47 x - 60

0 = x^{2} - 5 x + 4

8 + 2 t = 4 + 3 t

x^{3} - y^{6}

4 x^{2} + 6 x = 8